document.write( "Question 1177125: 7. In Alberta, 55% of new drivers take a driver training course before completing their driver’s test. Of the drivers that took training, 75% pass their driver’s test. Of the drivers that did not take training, 58% pass their driver’s test.\r
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document.write( "a. Complete the following tree diagram to represent the given information. Express the probability of each event to 4 decimal places if necessary. \r
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document.write( "Diagram: -------> i= P(training)------>iii= P(pass)----> vii= P(training AND pass)
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document.write( " -------> iv= P(fail)----> viii= P(training AND fail) \r
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document.write( " -------> ii= P(no training)-----> v= P(pass)-----> ix=P(no training AND pass)
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document.write( " ------> vi= P(fail)----> x= P(no training AND fail) \r
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document.write( "MY ANSWERS:
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document.write( "i. 55%
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document.write( "ii. 45%
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document.write( "iii. 75%
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document.write( "iv. 25%
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document.write( "v. 58%
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document.write( "vi. 42
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document.write( "vii. 0.42
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document.write( "viii. 0.14
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document.write( "ix. 0.26
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document.write( "x. 0.18
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document.write( "b. Jim passed his driver’s test. Use the values in your probability tree above to determine the probability that he took driver training, to the nearest whole percent? (1 mark)
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Algebra.Com's Answer #850517 by CPhill(1987) You can put this solution on YOUR website! It looks like you've got a good handle on the tree diagram and probabilities! Here's a breakdown with some minor corrections:\r \n" ); document.write( "\n" ); document.write( "**a. Completed Tree Diagram**\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( " --- P(Pass | Training) = 0.75 --> P(Training AND Pass) = 0.55 * 0.75 = 0.4125 \n" ); document.write( " / \n" ); document.write( " / \n" ); document.write( " P(Training) = 0.55 \n" ); document.write( " \ --- P(Fail | Training) = 0.25 --> P(Training AND Fail) = 0.55 * 0.25 = 0.1375 \n" ); document.write( " \ \n" ); document.write( " / \n" ); document.write( " --- P(Pass | No Training) = 0.58 --> P(No Training AND Pass) = 0.45 * 0.58 = 0.2610 \n" ); document.write( " \ \n" ); document.write( " / \n" ); document.write( " P(No Training) = 0.45 \n" ); document.write( " \ --- P(Fail | No Training) = 0.42 --> P(No Training AND Fail) = 0.45 * 0.42 = 0.1890 \n" ); document.write( " \ \n" ); document.write( " / \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "**Minor Corrections:**\r \n" ); document.write( "\n" ); document.write( "* **vii. P(Training AND Pass):** 0.55 * 0.75 = 0.4125 \n" ); document.write( "* **viii. P(Training AND Fail):** 0.55 * 0.25 = 0.1375 \n" ); document.write( "* **ix. P(No Training AND Pass):** 0.45 * 0.58 = 0.2610 \n" ); document.write( "* **x. P(No Training AND Fail):** 0.45 * 0.42 = 0.1890\r \n" ); document.write( "\n" ); document.write( "You had the right idea with the calculations, just a slight adjustment in the values for vii and viii.\r \n" ); document.write( "\n" ); document.write( "**b. Probability Jim Took Training Given He Passed**\r \n" ); document.write( "\n" ); document.write( "We want to find P(Training | Pass). We can use Bayes' Theorem:\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( "P(Training | Pass) = [P(Pass | Training) * P(Training)] / P(Pass) \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "To find P(Pass), we need to consider both ways someone can pass:\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( "P(Pass) = P(Training AND Pass) + P(No Training AND Pass) \n" ); document.write( "P(Pass) = 0.4125 + 0.2610 = 0.6735 \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "Now we can plug the values into Bayes' Theorem:\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( "P(Training | Pass) = (0.75 * 0.55) / 0.6735 \n" ); document.write( " ≈ 0.6126 \n" ); document.write( " ≈ 61% (to the nearest whole percent) \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "**Therefore, the probability that Jim took driver training given that he passed his test is approximately 61%.** \n" ); document.write( " |