document.write( "Question 1177158: A lot of 50 electrical components numbered 1 to 50 is drawn at random, one by one, and is
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document.write( "divided among five customers.
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document.write( "(a) Suppose that it is known that components 3, 18, 12, 26, and 46 are defective. What is
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document.write( "the probability that each customer will receive one defective component?
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document.write( "(b) What is the probability that one customer will have drawn five defective components?
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document.write( "(c) What is the probability that two customers will receive two defective components each,
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document.write( "two none, and the other one?\r
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Algebra.Com's Answer #850509 by CPhill(1987) You can put this solution on YOUR website! **Assumptions:**\r \n" ); document.write( "\n" ); document.write( "* Each component is equally likely to be drawn. \n" ); document.write( "* The drawing is done without replacement (once a component is drawn, it's not put back in).\r \n" ); document.write( "\n" ); document.write( "**(a) Probability that each customer receives one defective component:**\r \n" ); document.write( "\n" ); document.write( "1. **Calculate the total number of ways to distribute the components:** \n" ); document.write( " * Each of the 50 components can go to any of the 5 customers. \n" ); document.write( " * Total ways to distribute: 5^50\r \n" ); document.write( "\n" ); document.write( "2. **Calculate the number of ways to distribute one defective component to each customer:** \n" ); document.write( " * We need to assign one defective component to each customer. \n" ); document.write( " * Number of ways to assign defective components: 5! (5 factorial) \n" ); document.write( " * The remaining 45 non-defective components can be distributed among the customers in 5^45 ways.\r \n" ); document.write( "\n" ); document.write( "3. **Calculate the probability:** \n" ); document.write( " * Probability = (Favorable ways) / (Total ways) \n" ); document.write( " * Probability = (5! * 5^45) / 5^50 \n" ); document.write( " * Probability = 5! / 5^5 = 120 / 3125 = **0.0384**\r \n" ); document.write( "\n" ); document.write( "**(b) Probability that one customer has all five defective components:**\r \n" ); document.write( "\n" ); document.write( "1. **Choose the customer:** \n" ); document.write( " * There are 5 ways to choose the customer who gets all the defective components.\r \n" ); document.write( "\n" ); document.write( "2. **Calculate the probability for that customer:** \n" ); document.write( " * The probability that the first defective component goes to this customer is 1/5. \n" ); document.write( " * The probability that the second defective component also goes to this customer is 1/5 (since we're drawing without replacement). \n" ); document.write( " * And so on for all five defective components. \n" ); document.write( " * Probability for this customer = (1/5)^5\r \n" ); document.write( "\n" ); document.write( "3. **Calculate the probability for the remaining components:** \n" ); document.write( " * The remaining 45 components must go to the other 4 customers. \n" ); document.write( " * Probability for remaining components = 4^45 / 5^45\r \n" ); document.write( "\n" ); document.write( "4. **Calculate the overall probability:** \n" ); document.write( " * Probability = (5 ways to choose customer) * (Probability for that customer) * (Probability for remaining components) \n" ); document.write( " * Probability = 5 * (1/5)^5 * (4^45 / 5^45) = 4^45 / 5^49 ≈ **1.055 x 10^-6** (very small probability)\r \n" ); document.write( "\n" ); document.write( "**(c) Probability that two customers receive two defective components each, two none, and the other one:**\r \n" ); document.write( "\n" ); document.write( "1. **Choose the customers:** \n" ); document.write( " * There are 5C2 = 10 ways to choose the two customers who get two defective components each. \n" ); document.write( " * There are 3C2 = 3 ways to choose the two customers who get no defective components.\r \n" ); document.write( "\n" ); document.write( "2. **Assign defective components:** \n" ); document.write( " * We need to divide the 5 defective components into two groups of 2 and one group of 1. \n" ); document.write( " * Number of ways to do this: 5! / (2! * 2! * 1!) = 30\r \n" ); document.write( "\n" ); document.write( "3. **Calculate the probability for the chosen customers:** \n" ); document.write( " * The probability that the first two defective components go to the first chosen customer is (1/5) * (1/5). \n" ); document.write( " * The probability that the next two defective components go to the second chosen customer is (1/5) * (1/5). \n" ); document.write( " * The last defective component goes to the remaining customer with probability 1/5.\r \n" ); document.write( "\n" ); document.write( "4. **Calculate the probability for the remaining components:** \n" ); document.write( " * The remaining 45 components must be distributed so that the two chosen \"no defective\" customers only receive components from the remaining 45. \n" ); document.write( " * Probability for remaining components = (45! / (22! * 23!)) * (2/5)^22 * (2/5)^23\r \n" ); document.write( "\n" ); document.write( "5. **Calculate the overall probability:** \n" ); document.write( " * Probability = (Ways to choose customers) * (Ways to assign defective components) * (Probability for chosen customers) * (Probability for remaining components) \n" ); document.write( " * Probability = 10 * 3 * 30 * (1/5)^5 * (45! / (22! * 23!)) * (2/5)^22 * (2/5)^23 \n" ); document.write( " * This calculation is quite complex and best done with a calculator or computer. The approximate result is **0.114**. \n" ); document.write( " |