document.write( "Question 1209791: Factor 15x3 - 5x2 + 6x - 2 by grouping. What is the resulting expression?\r
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document.write( "(5x2 + 2)(3x - 1)
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document.write( "(5x2 - 2)(3x + 1)
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document.write( "(15x2 + 2)(x - 1)
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document.write( "(15x2 - 2)(x + 1) \n" );
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Algebra.Com's Answer #850447 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( " \n" ); document.write( "is an identity. This is a true equation for any x value you plug in. \n" ); document.write( "Verification using WolframAlpha (there are other similar online calculators) \n" ); document.write( "Alternatively you can FOIL out the expression (5x^2+2)(3x-1) to arrive back at 15x^3 - 5x^2 + 6x - 2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: Choice A \n" ); document.write( " \n" ); document.write( " |