document.write( "Question 1209791: Factor 15x3 - 5x2 + 6x - 2 by grouping. What is the resulting expression?\r
\n" ); document.write( "\n" ); document.write( "(5x2 + 2)(3x - 1)
\n" ); document.write( "(5x2 - 2)(3x + 1)
\n" ); document.write( "(15x2 + 2)(x - 1)
\n" ); document.write( "(15x2 - 2)(x + 1)
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Algebra.Com's Answer #850447 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "\"15x%5E3+-+5x%5E2+%2B+6x+-+2\"\r
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\n" ); document.write( "\n" ); document.write( "= \"%2815x%5E3+-+5x%5E2%29+%2B+%286x+-+2%29\" pairing terms into two groups\r
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\n" ); document.write( "\n" ); document.write( "= \"5x%5E2%283x+-+1%29+%2B+2%283x+-+1%29\" factor each group separately\r
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\n" ); document.write( "\n" ); document.write( "= \"%285x%5E2%2B2%29%283x+-+1%29\" pull out the GCF 3x-1\r
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\n" ); document.write( "\n" ); document.write( "Therefore,
\n" ); document.write( "\"15x%5E3+-+5x%5E2+%2B+6x+-+2=%285x%5E2%2B2%29%283x+-+1%29\"
\n" ); document.write( "is an identity. This is a true equation for any x value you plug in.
\n" ); document.write( "Verification using WolframAlpha (there are other similar online calculators)
\n" ); document.write( "Alternatively you can FOIL out the expression (5x^2+2)(3x-1) to arrive back at 15x^3 - 5x^2 + 6x - 2\r
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\n" ); document.write( "\n" ); document.write( "Answer: Choice A
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