document.write( "Question 1209785: A woman invests $72,000 in two ways - some at 5% and the remaining amount at 3%. Her total annual interest income is $4,130. Find the amount she invests at each rate. \n" ); document.write( "
Algebra.Com's Answer #850423 by josgarithmetic(39617)\"\" \"About 
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x invested at 5%, so 72000-x invested at 3%;\r
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\n" ); document.write( "\n" ); document.write( "\"0.05x%2B0.03%2872000-x%29=4130\"\r
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\n" ); document.write( "\"x=98500\"
\n" ); document.write( "Something is wrong. No way to invest in either interest rate more than the given amount of 72000 to invest.
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