document.write( "Question 1177980: A car is parked among N cars in a row, not at either end. On this return the owner finds that exactly r
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document.write( "of the N places are still occupied. What is the probability that both neighbouring places are empty. \n" );
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Algebra.Com's Answer #850391 by CPhill(2189) You can put this solution on YOUR website! Let's break down this problem step-by-step.\r \n" ); document.write( "\n" ); document.write( "Understanding the Problem\r \n" ); document.write( "\n" ); document.write( "Total Cars: N \n" ); document.write( "Our Car: Parked among N cars, not at either end. \n" ); document.write( "Remaining Cars: r (including our car) \n" ); document.write( "Goal: Find the probability that both neighboring places are empty. \n" ); document.write( "1. Total Possible Arrangements\r \n" ); document.write( "\n" ); document.write( "We know that r spots are occupied, including our car. Since our car's position is fixed, we need to choose the remaining r-1 spots from the N-1 available spots (excluding our car).\r \n" ); document.write( "\n" ); document.write( "Total ways to choose r-1 spots from N-1 spots: C(N-1, r-1) = (N-1)! / [(r-1)! * (N-r)!] \n" ); document.write( "2. Favorable Arrangements\r \n" ); document.write( "\n" ); document.write( "We want to find the arrangements where our car's two neighboring spots are empty.\r \n" ); document.write( "\n" ); document.write( "Fix Our Car: Our car's position is fixed.\r \n" ); document.write( "\n" ); document.write( "Empty Neighbors: The two spots next to our car must be empty.\r \n" ); document.write( "\n" ); document.write( "Remaining Spots: We have N - 3 remaining spots (excluding our car and its neighbors).\r \n" ); document.write( "\n" ); document.write( "Remaining Cars: We need to choose r - 1 spots from the N - 3 spots.\r \n" ); document.write( "\n" ); document.write( "Favorable ways to choose r-1 spots from N-3 spots: C(N-3, r-1) = (N-3)! / [(r-1)! * (N-r-2)!]\r \n" ); document.write( "\n" ); document.write( "3. Calculate the Probability\r \n" ); document.write( "\n" ); document.write( "The probability is the ratio of favorable arrangements to total arrangements:\r \n" ); document.write( "\n" ); document.write( "Probability = C(N-3, r-1) / C(N-1, r-1) \n" ); document.write( "Probability = [(N-3)! / ((r-1)! * (N-r-2)!)] / [(N-1)! / ((r-1)! * (N-r)!)] \n" ); document.write( "Probability = [(N-3)! / (N-r-2)!] * [(N-r)! / (N-1)!] \n" ); document.write( "Probability = [(N-3)! / (N-1)!] * [(N-r)! / (N-r-2)!] \n" ); document.write( "Probability = [1 / ((N-1)(N-2))] * [(N-r)(N-r-1)] \n" ); document.write( "Probability = [(N-r)(N-r-1)] / [(N-1)(N-2)] \n" ); document.write( "Therefore, the probability that both neighboring places are empty is [(N-r)(N-r-1)] / [(N-1)(N-2)]. \n" ); document.write( " |