document.write( "Question 1177981: The University of America runs two bus lines on campus: red and green. The red line serves north
\n" ); document.write( "campus and the green line serves south campus with a transfer station linking the two lines. Green
\n" ); document.write( "buses arrive randomly (according to a Poisson distribution) at the transfer station every 10 minutes.
\n" ); document.write( "Red buses also arrive randomly every 7 minutes.
\n" ); document.write( "(a) What is the probability that 2 buses will stop at the station during a 5 minute interval?
\n" ); document.write( "(b) A student whose dormitory is located next to the station has a class in 10 minutes. Either bus will
\n" ); document.write( "take the student to the classroom building. The ride takes 5 minutes, after which the student will walk
\n" ); document.write( "for around 3 minutes to reach the class room. What is the probability that the student will make it to
\n" ); document.write( "class on time?
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Algebra.Com's Answer #850390 by CPhill(1959)\"\" \"About 
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Let's solve this problem step-by-step.\r
\n" ); document.write( "\n" ); document.write( "**Understanding the Problem**\r
\n" ); document.write( "\n" ); document.write( "* **Green Buses:** Poisson distribution, arrival every 10 minutes (λ_green = 10 minutes)
\n" ); document.write( "* **Red Buses:** Poisson distribution, arrival every 7 minutes (λ_red = 7 minutes)\r
\n" ); document.write( "\n" ); document.write( "**(a) Probability of 2 Buses in a 5-Minute Interval**\r
\n" ); document.write( "\n" ); document.write( "1. **Calculate Arrival Rates for 5 Minutes**\r
\n" ); document.write( "\n" ); document.write( " * Green buses: λ_green(5) = (5 minutes / 10 minutes) = 0.5 buses
\n" ); document.write( " * Red buses: λ_red(5) = (5 minutes / 7 minutes) ≈ 0.7143 buses\r
\n" ); document.write( "\n" ); document.write( "2. **Calculate Total Arrival Rate**\r
\n" ); document.write( "\n" ); document.write( " * Total arrival rate (λ_total) = λ_green(5) + λ_red(5) = 0.5 + 0.7143 = 1.2143 buses\r
\n" ); document.write( "\n" ); document.write( "3. **Use Poisson Distribution Formula**\r
\n" ); document.write( "\n" ); document.write( " * P(X = k) = (e^(-λ) * λ^k) / k!\r
\n" ); document.write( "\n" ); document.write( " We want to find P(X = 2), where λ = 1.2143.\r
\n" ); document.write( "\n" ); document.write( " * P(X = 2) = (e^(-1.2143) * 1.2143^2) / 2!
\n" ); document.write( " * P(X = 2) = (0.2969 * 1.4745) / 2
\n" ); document.write( " * P(X = 2) ≈ 0.4378 / 2
\n" ); document.write( " * P(X = 2) ≈ 0.2189\r
\n" ); document.write( "\n" ); document.write( " Therefore, the probability that 2 buses will stop at the station during a 5-minute interval is approximately 0.2189.\r
\n" ); document.write( "\n" ); document.write( "**(b) Probability of Making it to Class on Time**\r
\n" ); document.write( "\n" ); document.write( "1. **Determine Arrival Rates for 10 Minutes**\r
\n" ); document.write( "\n" ); document.write( " * Green buses: λ_green(10) = (10 minutes / 10 minutes) = 1 bus
\n" ); document.write( " * Red buses: λ_red(10) = (10 minutes / 7 minutes) ≈ 1.4286 buses\r
\n" ); document.write( "\n" ); document.write( "2. **Calculate Probabilities of No Buses Arriving in 10 Minutes**\r
\n" ); document.write( "\n" ); document.write( " * P(Green = 0) = (e^(-1) * 1^0) / 0! = e^(-1) ≈ 0.3679
\n" ); document.write( " * P(Red = 0) = (e^(-1.4286) * 1.4286^0) / 0! = e^(-1.4286) ≈ 0.2394\r
\n" ); document.write( "\n" ); document.write( "3. **Calculate Probability of No Buses Arriving (Both Lines)**\r
\n" ); document.write( "\n" ); document.write( " * P(Green = 0 and Red = 0) = P(Green = 0) * P(Red = 0) = 0.3679 * 0.2394 ≈ 0.0881\r
\n" ); document.write( "\n" ); document.write( "4. **Calculate Probability of at Least One Bus Arriving**\r
\n" ); document.write( "\n" ); document.write( " * P(At least one bus) = 1 - P(Green = 0 and Red = 0) = 1 - 0.0881 = 0.9119\r
\n" ); document.write( "\n" ); document.write( "5. **Conclusion**\r
\n" ); document.write( "\n" ); document.write( " If at least one bus arrives within the 10 minute period, the student will have 5 minutes of travel time and 3 minutes of walking time, which will get them to class on time.\r
\n" ); document.write( "\n" ); document.write( " Therefore, the probability that the student will make it to class on time is approximately 0.9119.\r
\n" ); document.write( "\n" ); document.write( "**Results**\r
\n" ); document.write( "\n" ); document.write( "(a) The probability that 2 buses will stop at the station during a 5-minute interval is approximately 0.2189.
\n" ); document.write( "(b) The probability that the student will make it to class on time is approximately 0.9119.
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