document.write( "Question 1178026: An airline has surveyed a simple random sample of air travelers to find out whether they would be interested in paying a higher fare in order to have access to email during their flight:Of the 400 travelers surveyed, 80 said email access would be worth a slight extra cost. Construct a 95% confidence interval for the population proportion of air travelers to who are in favour of the airline's email idea. \n" ); document.write( "
Algebra.Com's Answer #850376 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's construct the 95% confidence interval for the population proportion of air travelers who are in favor of the airline's email idea.\r \n" ); document.write( "\n" ); document.write( "**1. Calculate the Sample Proportion (p̂)**\r \n" ); document.write( "\n" ); document.write( "* **Sample Size (n):** 400 \n" ); document.write( "* **Number in Favor (x):** 80 \n" ); document.write( "* **Sample Proportion (p̂):** p̂ = x / n = 80 / 400 = 0.20\r \n" ); document.write( "\n" ); document.write( "**2. Calculate the Standard Error (SE)**\r \n" ); document.write( "\n" ); document.write( "* **Standard Error (SE):** SE = √[p̂(1 - p̂) / n] \n" ); document.write( "* SE = √[0.20(1 - 0.20) / 400] \n" ); document.write( "* SE = √[0.20(0.80) / 400] \n" ); document.write( "* SE = √(0.16 / 400) \n" ); document.write( "* SE = √0.0004 = 0.02\r \n" ); document.write( "\n" ); document.write( "**3. Find the Critical Value (z*)**\r \n" ); document.write( "\n" ); document.write( "* **Confidence Level:** 95% \n" ); document.write( "* **Alpha (α):** 1 - 0.95 = 0.05 \n" ); document.write( "* **Alpha/2:** α/2 = 0.025 \n" ); document.write( "* **Critical Value (z*):** For a 95% confidence interval, z* = 1.96 (from the standard normal distribution table)\r \n" ); document.write( "\n" ); document.write( "**4. Calculate the Margin of Error (ME)**\r \n" ); document.write( "\n" ); document.write( "* **Margin of Error (ME):** ME = z* * SE \n" ); document.write( "* ME = 1.96 * 0.02 = 0.0392\r \n" ); document.write( "\n" ); document.write( "**5. Construct the Confidence Interval**\r \n" ); document.write( "\n" ); document.write( "* **Confidence Interval:** p̂ ± ME \n" ); document.write( "* **Lower Bound:** p̂ - ME = 0.20 - 0.0392 = 0.1608 \n" ); document.write( "* **Upper Bound:** p̂ + ME = 0.20 + 0.0392 = 0.2392\r \n" ); document.write( "\n" ); document.write( "**Therefore, the 95% confidence interval for the population proportion of air travelers who are in favor of the airline's email idea is (0.1608, 0.2392).** \n" ); document.write( " \n" ); document.write( " |