document.write( "Question 116942: find the length of a rectangle with 36cm as its diagonal \n" ); document.write( "
Algebra.Com's Answer #85036 by checkley71(8403)\"\" \"About 
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\n" ); document.write( "X^2+Y^2=36
\n" ); document.write( "IF X IS THE LENGTH OF 4 THEN:
\n" ); document.write( "16+Y^2=36
\n" ); document.write( "Y^2=36-16
\n" ); document.write( "Y^2=36-16
\n" ); document.write( "Y^2=20
\n" ); document.write( "Y=SQRT20
\n" ); document.write( "Y=4.47 FOR THE WIDTH
\n" ); document.write( "PROOF
\n" ); document.write( "4*2+4.4762=36
\n" ); document.write( "16+20=36
\n" ); document.write( "36=36
\n" ); document.write( "ALSO IF X IS THE LENGTH OF 5 THEN:
\n" ); document.write( "5^2+Y^2=36
\n" ); document.write( "25+Y^2=36
\n" ); document.write( "Y^2=36-25
\n" ); document.write( "Y^2=9
\n" ); document.write( "Y=SQRT9
\n" ); document.write( "Y=3 FOR THE WIDTH.
\n" ); document.write( "PROOF
\n" ); document.write( "5^2+3^2=36
\n" ); document.write( "25+9=36
\n" ); document.write( "36=36 \n" ); document.write( "
\n" );