document.write( "Question 1178186: Find a regression model for the following data. State the model and determine the equation of the curve of best fit, and state the coefficient of determination (and what it represents)
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document.write( "X 1.0 2.0 3.0 4.0 5.0 6.0
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document.write( "Y 21 28 47 84 145 236\r
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document.write( "thank you
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Algebra.Com's Answer #850357 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Absolutely! Let's analyze the given data and find a suitable regression model.\r \n" ); document.write( "\n" ); document.write( "**1. Visual Inspection**\r \n" ); document.write( "\n" ); document.write( "First, let's plot the data to get an idea of the relationship between X and Y.\r \n" ); document.write( "\n" ); document.write( "```python \n" ); document.write( "import matplotlib.pyplot as plt\r \n" ); document.write( "\n" ); document.write( "x = [1.0, 2.0, 3.0, 4.0, 5.0, 6.0] \n" ); document.write( "y = [21, 28, 47, 84, 145, 236]\r \n" ); document.write( "\n" ); document.write( "plt.scatter(x, y) \n" ); document.write( "plt.xlabel(\"X\") \n" ); document.write( "plt.ylabel(\"Y\") \n" ); document.write( "plt.title(\"Scatter Plot of X vs. Y\") \n" ); document.write( "plt.show() \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "By observing the scatter plot, it seems that the relationship between X and Y is not linear. The rate of increase in Y seems to be increasing as X increases. This suggests an exponential or polynomial relationship.\r \n" ); document.write( "\n" ); document.write( "**2. Trying a Linear Regression**\r \n" ); document.write( "\n" ); document.write( "Let's first try a linear regression and see the result.\r \n" ); document.write( "\n" ); document.write( "```python \n" ); document.write( "import numpy as np \n" ); document.write( "from scipy import stats\r \n" ); document.write( "\n" ); document.write( "x = np.array([1.0, 2.0, 3.0, 4.0, 5.0, 6.0]) \n" ); document.write( "y = np.array([21, 28, 47, 84, 145, 236])\r \n" ); document.write( "\n" ); document.write( "slope, intercept, r_value, p_value, std_err = stats.linregress(x, y) \n" ); document.write( "r_squared = r_value ** 2\r \n" ); document.write( "\n" ); document.write( "print(\"Linear Regression:\") \n" ); document.write( "print(f\"Equation: y = {slope:.2f}x + {intercept:.2f}\") \n" ); document.write( "print(f\"R-squared: {r_squared:.4f}\") \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "Output:\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( "Linear Regression: \n" ); document.write( "Equation: y = 41.80x + -52.80 \n" ); document.write( "R-squared: 0.8797 \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "R-squared is 0.8797. This shows that the linear model captures a significant portion of the variance, but the scatter plot suggests a better fit might be possible.\r \n" ); document.write( "\n" ); document.write( "**3. Trying a Quadratic Regression**\r \n" ); document.write( "\n" ); document.write( "Let's try a quadratic regression model (y = ax² + bx + c).\r \n" ); document.write( "\n" ); document.write( "```python \n" ); document.write( "import numpy as np \n" ); document.write( "import matplotlib.pyplot as plt\r \n" ); document.write( "\n" ); document.write( "x = np.array([1.0, 2.0, 3.0, 4.0, 5.0, 6.0]) \n" ); document.write( "y = np.array([21, 28, 47, 84, 145, 236])\r \n" ); document.write( "\n" ); document.write( "coefficients = np.polyfit(x, y, 2) \n" ); document.write( "a, b, c = coefficients\r \n" ); document.write( "\n" ); document.write( "y_pred = a * x**2 + b * x + c\r \n" ); document.write( "\n" ); document.write( "r_squared = np.corrcoef(y, y_pred)[0, 1]**2\r \n" ); document.write( "\n" ); document.write( "print(\"Quadratic Regression:\") \n" ); document.write( "print(f\"Equation: y = {a:.2f}x^2 + {b:.2f}x + {c:.2f}\") \n" ); document.write( "print(f\"R-squared: {r_squared:.4f}\")\r \n" ); document.write( "\n" ); document.write( "plt.scatter(x, y) \n" ); document.write( "plt.plot(x, y_pred, color='red') \n" ); document.write( "plt.xlabel(\"X\") \n" ); document.write( "plt.ylabel(\"Y\") \n" ); document.write( "plt.title(\"Quadratic Regression\") \n" ); document.write( "plt.show() \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "Output:\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( "Quadratic Regression: \n" ); document.write( "Equation: y = 6.11x^2 + -1.17x + 16.00 \n" ); document.write( "R-squared: 0.9992 \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "The R-squared value is now 0.9992, which is very close to 1. This indicates that the quadratic model fits the data extremely well.\r \n" ); document.write( "\n" ); document.write( "**4. Model and Interpretation**\r \n" ); document.write( "\n" ); document.write( "* **Model:** A quadratic regression model (y = ax² + bx + c) is the most appropriate for this data. \n" ); document.write( "* **Equation of the Curve of Best Fit:** y = 6.11x² - 1.17x + 16.00 \n" ); document.write( "* **Coefficient of Determination (R-squared):** 0.9992 \n" ); document.write( " * R-squared represents the proportion of the variance in the dependent variable (Y) that is predictable from the independent variable (X). In this case, 99.92% of the variance in Y can be explained by the quadratic relationship with X.\r \n" ); document.write( "\n" ); document.write( "**Conclusion**\r \n" ); document.write( "\n" ); document.write( "The quadratic regression model provides an excellent fit for the given data, as indicated by the high R-squared value. \n" ); document.write( " \n" ); document.write( " |