document.write( "Question 1178442: Let Y have a chi-square distribution with 15 degrees of freedom. Find the following probabilities.
\n" );
document.write( "(a) P (Y ≤ y0) = 0.025
\n" );
document.write( "(b) P (a
\n" );
document.write( "\n" );
document.write( "thank you
Algebra.Com's Answer #850348 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's find the probabilities for a chi-square distribution with 15 degrees of freedom.\r \n" ); document.write( "\n" ); document.write( "**(a) P(Y ≤ y0) = 0.025**\r \n" ); document.write( "\n" ); document.write( "* We are looking for the value y0 such that 2.5% of the chi-square distribution is to the left of it. \n" ); document.write( "* This is the 2.5th percentile of the chi-square distribution with 15 degrees of freedom.\r \n" ); document.write( "\n" ); document.write( "**(b) P(a < Y < b) = 0.90**\r \n" ); document.write( "\n" ); document.write( "* We want to find the values a and b such that 90% of the chi-square distribution lies between them. \n" ); document.write( "* This means we want to exclude the lower 5% and the upper 5%. \n" ); document.write( "* Therefore, 'a' is the 5th percentile, and 'b' is the 95th percentile.\r \n" ); document.write( "\n" ); document.write( "**(c) P(Y ≥ 22.307)**\r \n" ); document.write( "\n" ); document.write( "* We want to find the probability that Y is greater than or equal to 22.307. \n" ); document.write( "* This is the area to the right of 22.307 under the chi-square curve.\r \n" ); document.write( "\n" ); document.write( "**Calculations**\r \n" ); document.write( "\n" ); document.write( "Using the `scipy.stats` library in Python:\r \n" ); document.write( "\n" ); document.write( "```python \n" ); document.write( "import scipy.stats as stats\r \n" ); document.write( "\n" ); document.write( "df = 15 # Degrees of freedom\r \n" ); document.write( "\n" ); document.write( "# (a) \n" ); document.write( "y0 = stats.chi2.ppf(0.025, df) \n" ); document.write( "print(f\"(a) y0 = {y0:.4f}\")\r \n" ); document.write( "\n" ); document.write( "# (b) \n" ); document.write( "a = stats.chi2.ppf(0.05, df) \n" ); document.write( "b = stats.chi2.ppf(0.95, df) \n" ); document.write( "print(f\"(b) a = {a:.4f}, b = {b:.4f}\")\r \n" ); document.write( "\n" ); document.write( "# (c) \n" ); document.write( "prob_c = 1 - stats.chi2.cdf(22.307, df) \n" ); document.write( "print(f\"(c) P(Y >= 22.307) = {prob_c:.4f}\") \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "**Results**\r \n" ); document.write( "\n" ); document.write( "* **(a) y0 = 6.2621** \n" ); document.write( "* **(b) a = 7.2609, b = 24.9958** \n" ); document.write( "* **(c) P(Y ≥ 22.307) = 0.1000** \n" ); document.write( " \n" ); document.write( " |