document.write( "Question 1178756: A natural history museum borrows $2,000,000 at simple annual interest to purchase new exhibits. Some of the money is borrowed at 5%, some at 6.5%, and some at 7.5%. Use a system of linear equations to determine how much is borrowed at each rate given that the total annual interest is $121,250 and the amount borrowed at 6.5% is four times the amount borrowed at 7.5%. Solve the system of linear equations using matrices.\r
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Algebra.Com's Answer #850300 by CPhill(1987) You can put this solution on YOUR website! Let's set up the system of linear equations and solve it using matrices.\r \n" ); document.write( "\n" ); document.write( "**1. Define the Variables:**\r \n" ); document.write( "\n" ); document.write( "* x = amount borrowed at 5% \n" ); document.write( "* y = amount borrowed at 6.5% \n" ); document.write( "* z = amount borrowed at 7.5%\r \n" ); document.write( "\n" ); document.write( "**2. Formulate the Equations:**\r \n" ); document.write( "\n" ); document.write( "* **Total Amount Borrowed:** x + y + z = 2,000,000 \n" ); document.write( "* **Total Annual Interest:** 0.05x + 0.065y + 0.075z = 121,250 \n" ); document.write( "* **Relationship Between y and z:** y = 4z\r \n" ); document.write( "\n" ); document.write( "**3. Rewrite the Equations in Standard Form:**\r \n" ); document.write( "\n" ); document.write( "1. x + y + z = 2,000,000 \n" ); document.write( "2. 0.05x + 0.065y + 0.075z = 121,250 \n" ); document.write( "3. 0x + y - 4z = 0\r \n" ); document.write( "\n" ); document.write( "To simplify the second equation, multiply it by 1000:\r \n" ); document.write( "\n" ); document.write( "1. x + y + z = 2,000,000 \n" ); document.write( "2. 50x + 65y + 75z = 121,250,000 \n" ); document.write( "3. y - 4z = 0\r \n" ); document.write( "\n" ); document.write( "**4. Represent the System as an Augmented Matrix:**\r \n" ); document.write( "\n" ); document.write( "``` \n" ); document.write( "[ 1 1 1 | 2000000 ] \n" ); document.write( "[ 50 65 75 | 121250000 ] \n" ); document.write( "[ 0 1 -4 | 0 ] \n" ); document.write( "```\r \n" ); document.write( "\n" ); document.write( "**5. Solve Using Row Operations:**\r \n" ); document.write( "\n" ); document.write( "1. **Eliminate x from the second row:** \n" ); document.write( " * R2 = R2 - 50 * R1 \n" ); document.write( " ``` \n" ); document.write( " [ 1 1 1 | 2000000 ] \n" ); document.write( " [ 0 15 25 | 21250000 ] \n" ); document.write( " [ 0 1 -4 | 0 ] \n" ); document.write( " ```\r \n" ); document.write( "\n" ); document.write( "2. **Swap R2 and R3 to make R2 easier to work with:** \n" ); document.write( " ``` \n" ); document.write( " [ 1 1 1 | 2000000 ] \n" ); document.write( " [ 0 1 -4 | 0 ] \n" ); document.write( " [ 0 15 25 | 21250000 ] \n" ); document.write( " ```\r \n" ); document.write( "\n" ); document.write( "3. **Eliminate y from the third row:** \n" ); document.write( " * R3 = R3 - 15 * R2 \n" ); document.write( " ``` \n" ); document.write( " [ 1 1 1 | 2000000 ] \n" ); document.write( " [ 0 1 -4 | 0 ] \n" ); document.write( " [ 0 0 85 | 21250000 ] \n" ); document.write( " ```\r \n" ); document.write( "\n" ); document.write( "4. **Solve for z:** \n" ); document.write( " * 85z = 21,250,000 \n" ); document.write( " * z = 21,250,000 / 85 \n" ); document.write( " * z = 250,000\r \n" ); document.write( "\n" ); document.write( "5. **Solve for y:** \n" ); document.write( " * y - 4z = 0 \n" ); document.write( " * y = 4z \n" ); document.write( " * y = 4 * 250,000 \n" ); document.write( " * y = 1,000,000\r \n" ); document.write( "\n" ); document.write( "6. **Solve for x:** \n" ); document.write( " * x + y + z = 2,000,000 \n" ); document.write( " * x = 2,000,000 - y - z \n" ); document.write( " * x = 2,000,000 - 1,000,000 - 250,000 \n" ); document.write( " * x = 750,000\r \n" ); document.write( "\n" ); document.write( "**6. Answers:**\r \n" ); document.write( "\n" ); document.write( "* Amount borrowed at 5% (x): $750,000 \n" ); document.write( "* Amount borrowed at 6.5% (y): $1,000,000 \n" ); document.write( "* Amount borrowed at 7.5% (z): $250,000 \n" ); document.write( " \n" ); document.write( " |