document.write( "Question 1178756: A natural history museum borrows $2,000,000 at simple annual interest to purchase new exhibits. Some of the money is borrowed at 5%, some at 6.5%, and some at 7.5%. Use a system of linear equations to determine how much is borrowed at each rate given that the total annual interest is $121,250 and the amount borrowed at 6.5% is four times the amount borrowed at 7.5%. Solve the system of linear equations using matrices.\r
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Algebra.Com's Answer #850300 by CPhill(1987)\"\" \"About 
You can put this solution on YOUR website!
Let's set up the system of linear equations and solve it using matrices.\r
\n" ); document.write( "\n" ); document.write( "**1. Define the Variables:**\r
\n" ); document.write( "\n" ); document.write( "* x = amount borrowed at 5%
\n" ); document.write( "* y = amount borrowed at 6.5%
\n" ); document.write( "* z = amount borrowed at 7.5%\r
\n" ); document.write( "\n" ); document.write( "**2. Formulate the Equations:**\r
\n" ); document.write( "\n" ); document.write( "* **Total Amount Borrowed:** x + y + z = 2,000,000
\n" ); document.write( "* **Total Annual Interest:** 0.05x + 0.065y + 0.075z = 121,250
\n" ); document.write( "* **Relationship Between y and z:** y = 4z\r
\n" ); document.write( "\n" ); document.write( "**3. Rewrite the Equations in Standard Form:**\r
\n" ); document.write( "\n" ); document.write( "1. x + y + z = 2,000,000
\n" ); document.write( "2. 0.05x + 0.065y + 0.075z = 121,250
\n" ); document.write( "3. 0x + y - 4z = 0\r
\n" ); document.write( "\n" ); document.write( "To simplify the second equation, multiply it by 1000:\r
\n" ); document.write( "\n" ); document.write( "1. x + y + z = 2,000,000
\n" ); document.write( "2. 50x + 65y + 75z = 121,250,000
\n" ); document.write( "3. y - 4z = 0\r
\n" ); document.write( "\n" ); document.write( "**4. Represent the System as an Augmented Matrix:**\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "[ 1 1 1 | 2000000 ]
\n" ); document.write( "[ 50 65 75 | 121250000 ]
\n" ); document.write( "[ 0 1 -4 | 0 ]
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "**5. Solve Using Row Operations:**\r
\n" ); document.write( "\n" ); document.write( "1. **Eliminate x from the second row:**
\n" ); document.write( " * R2 = R2 - 50 * R1
\n" ); document.write( " ```
\n" ); document.write( " [ 1 1 1 | 2000000 ]
\n" ); document.write( " [ 0 15 25 | 21250000 ]
\n" ); document.write( " [ 0 1 -4 | 0 ]
\n" ); document.write( " ```\r
\n" ); document.write( "\n" ); document.write( "2. **Swap R2 and R3 to make R2 easier to work with:**
\n" ); document.write( " ```
\n" ); document.write( " [ 1 1 1 | 2000000 ]
\n" ); document.write( " [ 0 1 -4 | 0 ]
\n" ); document.write( " [ 0 15 25 | 21250000 ]
\n" ); document.write( " ```\r
\n" ); document.write( "\n" ); document.write( "3. **Eliminate y from the third row:**
\n" ); document.write( " * R3 = R3 - 15 * R2
\n" ); document.write( " ```
\n" ); document.write( " [ 1 1 1 | 2000000 ]
\n" ); document.write( " [ 0 1 -4 | 0 ]
\n" ); document.write( " [ 0 0 85 | 21250000 ]
\n" ); document.write( " ```\r
\n" ); document.write( "\n" ); document.write( "4. **Solve for z:**
\n" ); document.write( " * 85z = 21,250,000
\n" ); document.write( " * z = 21,250,000 / 85
\n" ); document.write( " * z = 250,000\r
\n" ); document.write( "\n" ); document.write( "5. **Solve for y:**
\n" ); document.write( " * y - 4z = 0
\n" ); document.write( " * y = 4z
\n" ); document.write( " * y = 4 * 250,000
\n" ); document.write( " * y = 1,000,000\r
\n" ); document.write( "\n" ); document.write( "6. **Solve for x:**
\n" ); document.write( " * x + y + z = 2,000,000
\n" ); document.write( " * x = 2,000,000 - y - z
\n" ); document.write( " * x = 2,000,000 - 1,000,000 - 250,000
\n" ); document.write( " * x = 750,000\r
\n" ); document.write( "\n" ); document.write( "**6. Answers:**\r
\n" ); document.write( "\n" ); document.write( "* Amount borrowed at 5% (x): $750,000
\n" ); document.write( "* Amount borrowed at 6.5% (y): $1,000,000
\n" ); document.write( "* Amount borrowed at 7.5% (z): $250,000
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