document.write( "Question 1178849: You are given the following sample data for variables x and y:
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document.write( "X (independent) | Y (dependent)|
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document.write( "1 | 16 |
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document.write( "7 | 50 |
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document.write( "3 | 22 |
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document.write( "8 | 59 |
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document.write( "11 | 63 |
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document.write( "5 | 46 |
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document.write( "4 | 43 |\r
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document.write( "1. Construct a scatter plot for these data and describe what, if any, relationship
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document.write( "appears to exist.
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document.write( "2. Calculate product-moment correlation and verify the answer by relating to
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document.write( "scatter plot you derived from the previous question.
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document.write( "3. Compute the regression equation based on these sample data and interpret the
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document.write( "regression coefficients.
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document.write( "4. Based on the sample data, what percentage of the total variation in the dependent
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document.write( "the variable can be explained by the independent variable?
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document.write( "5.Explain why spearman rank correlation coefficient is not suitable to analyze
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document.write( "above data set? \n" );
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Algebra.Com's Answer #850287 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this problem step-by-step:\r \n" ); document.write( "\n" ); document.write( "**1. Construct a Scatter Plot and Describe the Relationship:**\r \n" ); document.write( "\n" ); document.write( "* **Scatter Plot:** \n" ); document.write( " * Plot the points (1, 16), (7, 50), (3, 22), (8, 59), (11, 63), (5, 46), and (4, 43) on a graph with x on the horizontal axis and y on the vertical axis. \n" ); document.write( " * You'll observe that as x increases, y tends to increase as well. \n" ); document.write( "* **Relationship:** \n" ); document.write( " * There appears to be a **positive linear relationship** between x and y. As the independent variable (x) increases, the dependent variable (y) also tends to increase. The points roughly follow a straight line pattern.\r \n" ); document.write( "\n" ); document.write( "**2. Calculate Product-Moment Correlation (Pearson's r):**\r \n" ); document.write( "\n" ); document.write( "* **Formula:** \n" ); document.write( " * r = [n(∑xy) - (∑x)(∑y)] / √{[n∑x² - (∑x)²][n∑y² - (∑y)²]} \n" ); document.write( "* **Calculations:** \n" ); document.write( " * n = 7 \n" ); document.write( " * ∑x = 1 + 7 + 3 + 8 + 11 + 5 + 4 = 39 \n" ); document.write( " * ∑y = 16 + 50 + 22 + 59 + 63 + 46 + 43 = 299 \n" ); document.write( " * ∑x² = 1² + 7² + 3² + 8² + 11² + 5² + 4² = 275 \n" ); document.write( " * ∑y² = 16² + 50² + 22² + 59² + 63² + 46² + 43² = 14,795 \n" ); document.write( " * ∑xy = (1 * 16) + (7 * 50) + (3 * 22) + (8 * 59) + (11 * 63) + (5 * 46) + (4 * 43) = 1,939 \n" ); document.write( " * r = [7(1939) - (39)(299)] / √{[7(275) - (39)²][7(14795) - (299)²]} \n" ); document.write( " * r = [13573 - 11661] / √{[1925 - 1521][103565 - 89401]} \n" ); document.write( " * r = 1912 / √[404 * 14164] \n" ); document.write( " * r = 1912 / √5723256 \n" ); document.write( " * r = 1912 / 2392.33 \n" ); document.write( " * r ≈ 0.7992 \n" ); document.write( "* **Verification:** \n" ); document.write( " * The calculated r (0.7992) is positive and relatively close to 1, indicating a strong positive linear relationship. This aligns with the scatter plot, which shows a positive linear trend.\r \n" ); document.write( "\n" ); document.write( "**3. Compute the Regression Equation and Interpret Coefficients:**\r \n" ); document.write( "\n" ); document.write( "* **Regression Equation:** y = a + bx \n" ); document.write( "* **Calculate b (slope):** \n" ); document.write( " * b = [n(∑xy) - (∑x)(∑y)] / [n(∑x²) - (∑x)²] \n" ); document.write( " * b = 1912 / 404 \n" ); document.write( " * b ≈ 4.7327 \n" ); document.write( "* **Calculate a (y-intercept):** \n" ); document.write( " * a = (∑y / n) - b(∑x / n) \n" ); document.write( " * a = (299 / 7) - 4.7327(39 / 7) \n" ); document.write( " * a ≈ 42.7143 - 26.3379 \n" ); document.write( " * a ≈ 16.3764 \n" ); document.write( "* **Regression Equation:** y = 16.3764 + 4.7327x \n" ); document.write( "* **Interpretation:** \n" ); document.write( " * **b (4.7327):** For every one-unit increase in x, y is predicted to increase by approximately 4.7327 units. \n" ); document.write( " * **a (16.3764):** When x is 0, the predicted value of y is approximately 16.3764.\r \n" ); document.write( "\n" ); document.write( "**4. Percentage of Total Variation Explained (R²):**\r \n" ); document.write( "\n" ); document.write( "* **R² = r²** (coefficient of determination) \n" ); document.write( "* R² = (0.7992)² \n" ); document.write( "* R² ≈ 0.6387 \n" ); document.write( "* **Percentage:** 0.6387 * 100% ≈ 63.87% \n" ); document.write( "* **Interpretation:** Approximately 63.87% of the total variation in y can be explained by the linear relationship with x.\r \n" ); document.write( "\n" ); document.write( "**5. Why Spearman Rank Correlation is Not Suitable:**\r \n" ); document.write( "\n" ); document.write( "* **Spearman Rank Correlation:** This coefficient measures the strength and direction of a monotonic relationship (not necessarily linear) between two ranked variables. It's used when data might not be normally distributed or when relationships are not strictly linear. \n" ); document.write( "* **Suitability for Pearson's r:** The data appears to have a relatively strong linear relationship, as observed in the scatter plot and confirmed by a high Pearson's r value (0.7992). \n" ); document.write( "* **Unnecessary Ranking:** Spearman's rank correlation requires ranking the data. If the relationship is adequately linear, ranking the data loses the magnitude of the differences between the values. \n" ); document.write( "* **Pearson's r is More Powerful:** For linear relationships and normally distributed data (or at least data that don't violate the assumptions of linear regression), Pearson's r is generally considered more powerful and informative than Spearman's rank correlation. \n" ); document.write( "* **Conclusion:** Since the scatter plot suggests a linear relationship, and Pearson's r shows a strong linear correlation, there is no need to rank the data. Pearson's r is more appropriate in this scenario. \n" ); document.write( " \n" ); document.write( " |