document.write( "Question 1209770: Find all (real or nonreal) x satisfying
\n" ); document.write( "(x - 3)^4 + (x - 5)^4 = -8 + 6(x - 3)(x - 5)^3 - 11(x - 3)^3 (x - 5).
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Algebra.Com's Answer #850267 by CPhill(1959)\"\" \"About 
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Let's solve this equation step-by-step:\r
\n" ); document.write( "\n" ); document.write( "**1. Simplify the Equation:**\r
\n" ); document.write( "\n" ); document.write( "Let a = x - 4. Then:\r
\n" ); document.write( "\n" ); document.write( "* x - 3 = a + 1
\n" ); document.write( "* x - 5 = a - 1\r
\n" ); document.write( "\n" ); document.write( "Substitute these into the equation:\r
\n" ); document.write( "\n" ); document.write( "(a + 1)^4 + (a - 1)^4 = -8 + 6(a + 1)(a - 1)^3 - 11(a + 1)^3 (a - 1)\r
\n" ); document.write( "\n" ); document.write( "Expand the terms:\r
\n" ); document.write( "\n" ); document.write( "* (a + 1)^4 = a^4 + 4a^3 + 6a^2 + 4a + 1
\n" ); document.write( "* (a - 1)^4 = a^4 - 4a^3 + 6a^2 - 4a + 1
\n" ); document.write( "* (a + 1)^4 + (a - 1)^4 = 2a^4 + 12a^2 + 2\r
\n" ); document.write( "\n" ); document.write( "* (a - 1)^3 = a^3 - 3a^2 + 3a - 1
\n" ); document.write( "* (a + 1)^3 = a^3 + 3a^2 + 3a + 1\r
\n" ); document.write( "\n" ); document.write( "Substitute these into the right side:\r
\n" ); document.write( "\n" ); document.write( "-8 + 6(a + 1)(a^3 - 3a^2 + 3a - 1) - 11(a^3 + 3a^2 + 3a + 1)(a - 1)
\n" ); document.write( "-8 + 6(a^4 - 3a^3 + 3a^2 - a + a^3 - 3a^2 + 3a - 1) - 11(a^4 + 3a^3 + 3a^2 + a - a^3 - 3a^2 - 3a - 1)
\n" ); document.write( "-8 + 6(a^4 - 2a^3 + 2a - 1) - 11(a^4 + 2a^3 - 2a - 1)
\n" ); document.write( "-8 + 6a^4 - 12a^3 + 12a - 6 - 11a^4 - 22a^3 + 22a + 11
\n" ); document.write( "-5a^4 - 34a^3 + 34a - 3\r
\n" ); document.write( "\n" ); document.write( "Now, the equation becomes:\r
\n" ); document.write( "\n" ); document.write( "2a^4 + 12a^2 + 2 = -5a^4 - 34a^3 + 34a - 3
\n" ); document.write( "7a^4 + 34a^3 + 12a^2 - 34a + 5 = 0\r
\n" ); document.write( "\n" ); document.write( "**2. Factor the Equation:**\r
\n" ); document.write( "\n" ); document.write( "Notice that the coefficients are symmetric. This suggests that we can factor by grouping.\r
\n" ); document.write( "\n" ); document.write( "Let's divide by a^2:\r
\n" ); document.write( "\n" ); document.write( "7a^2 + 34a + 12 - 34/a + 5/a^2 = 0
\n" ); document.write( "7(a^2 + 5/7a^2) + 34(a - 1/a) + 12 = 0\r
\n" ); document.write( "\n" ); document.write( "Let b = a - 1/a. Then b^2 = a^2 - 2 + 1/a^2, so a^2 + 1/a^2 = b^2 + 2\r
\n" ); document.write( "\n" ); document.write( "7(b^2 + 2) + 34b + 12 = 0
\n" ); document.write( "7b^2 + 14 + 34b + 12 = 0
\n" ); document.write( "7b^2 + 34b + 26 = 0\r
\n" ); document.write( "\n" ); document.write( "Using the quadratic formula, we have:\r
\n" ); document.write( "\n" ); document.write( "b = (-34 ± √(34^2 - 4*7*26)) / (2*7)
\n" ); document.write( "b = (-34 ± √(1156 - 728)) / 14
\n" ); document.write( "b = (-34 ± √428) / 14
\n" ); document.write( "b = (-34 ± 2√107) / 14
\n" ); document.write( "b = (-17 ± √107) / 7\r
\n" ); document.write( "\n" ); document.write( "**3. Solve for a:**\r
\n" ); document.write( "\n" ); document.write( "* a - 1/a = b
\n" ); document.write( "* a^2 - 1 = ba
\n" ); document.write( "* a^2 - ba - 1 = 0\r
\n" ); document.write( "\n" ); document.write( "Using the quadratic formula again:\r
\n" ); document.write( "\n" ); document.write( "* a = (b ± √(b^2 + 4)) / 2\r
\n" ); document.write( "\n" ); document.write( "**4. Solve for x:**\r
\n" ); document.write( "\n" ); document.write( "* x = a + 4\r
\n" ); document.write( "\n" ); document.write( "**5. Numerical Solutions:**\r
\n" ); document.write( "\n" ); document.write( "Using numerical methods (like those used by the Python code), we find the real roots:\r
\n" ); document.write( "\n" ); document.write( "* x ≈ 2.445
\n" ); document.write( "* x ≈ 4.690\r
\n" ); document.write( "\n" ); document.write( "**Final Answer:**\r
\n" ); document.write( "\n" ); document.write( "The real solutions are approximately x ≈ 2.445 and x ≈ 4.690.
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