document.write( "Question 1179081: Nick has been depositing $ 190 in a savings account every three months for the past three years. This account paid 3 % convertible quarterly. Nick has just made the last deposit. Nick is buying a car for $ 14000. He is taking out a car loan. He will use the accumulated value of his savings account as the downpayment on the car. The loan is at 3 % convertible semiannually and has a term of 4 years. Find the size of Nick's monthly car loan payment. \n" ); document.write( "
Algebra.Com's Answer #850265 by CPhill(1959)\"\" \"About 
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Let's break this problem into two parts:\r
\n" ); document.write( "\n" ); document.write( "**Part 1: Calculate the Accumulated Value of Nick's Savings Account**\r
\n" ); document.write( "\n" ); document.write( "1. **Deposits:** $190 every three months (quarterly)
\n" ); document.write( "2. **Time Period:** 3 years
\n" ); document.write( "3. **Interest Rate:** 3% convertible quarterly (0.03/4 = 0.0075 per quarter)
\n" ); document.write( "4. **Number of Deposits:** 3 years * 4 quarters/year = 12 deposits\r
\n" ); document.write( "\n" ); document.write( "We can use the future value of an ordinary annuity formula:\r
\n" ); document.write( "\n" ); document.write( "FV = P * [((1 + r)^n - 1) / r]\r
\n" ); document.write( "\n" ); document.write( "Where:\r
\n" ); document.write( "\n" ); document.write( "* FV = Future Value
\n" ); document.write( "* P = Periodic Payment ($190)
\n" ); document.write( "* r = Interest Rate per Period (0.0075)
\n" ); document.write( "* n = Number of Periods (12)\r
\n" ); document.write( "\n" ); document.write( "FV = 190 * [((1 + 0.0075)^12 - 1) / 0.0075]
\n" ); document.write( "FV = 190 * [(1.0075^12 - 1) / 0.0075]
\n" ); document.write( "FV = 190 * [(1.093806897 - 1) / 0.0075]
\n" ); document.write( "FV = 190 * [0.093806897 / 0.0075]
\n" ); document.write( "FV = 190 * 12.50758627
\n" ); document.write( "FV ≈ $2376.44\r
\n" ); document.write( "\n" ); document.write( "**Part 2: Calculate Nick's Monthly Car Loan Payment**\r
\n" ); document.write( "\n" ); document.write( "1. **Car Price:** $14,000
\n" ); document.write( "2. **Down Payment:** $2376.44 (from the savings account)
\n" ); document.write( "3. **Loan Amount:** $14,000 - $2376.44 = $11,623.56
\n" ); document.write( "4. **Loan Term:** 4 years
\n" ); document.write( "5. **Interest Rate:** 3% convertible semiannually (0.03/2 = 0.015 per 6 months)
\n" ); document.write( "6. **Number of Semiannual Periods:** 4 years * 2 = 8
\n" ); document.write( "7. **Number of Monthly Payments:** 4 years * 12 months/year = 48\r
\n" ); document.write( "\n" ); document.write( "First, we need to find the equivalent monthly interest rate.\r
\n" ); document.write( "\n" ); document.write( "* (1 + 0.015)^2 = 1.030225. This is the effective annual rate.
\n" ); document.write( "* (1.030225)^(1/12) = 1.002470126. This is the monthly multiplier.
\n" ); document.write( "* Monthly Interest Rate = 1.002470126 - 1 = 0.002470126\r
\n" ); document.write( "\n" ); document.write( "Now, we can use the loan payment formula:\r
\n" ); document.write( "\n" ); document.write( "M = P * [r(1 + r)^n] / [(1 + r)^n - 1]\r
\n" ); document.write( "\n" ); document.write( "Where:\r
\n" ); document.write( "\n" ); document.write( "* M = Monthly Payment
\n" ); document.write( "* P = Loan Amount ($11,623.56)
\n" ); document.write( "* r = Monthly Interest Rate (0.002470126)
\n" ); document.write( "* n = Number of Monthly Payments (48)\r
\n" ); document.write( "\n" ); document.write( "M = 11623.56 * [0.002470126 * (1.002470126)^48] / [(1.002470126)^48 - 1]
\n" ); document.write( "M = 11623.56 * [0.002470126 * 1.127493457] / [1.127493457 - 1]
\n" ); document.write( "M = 11623.56 * [0.002785721] / [0.127493457]
\n" ); document.write( "M = 11623.56 * 0.021850327
\n" ); document.write( "M ≈ $253.97\r
\n" ); document.write( "\n" ); document.write( "**Answer:**\r
\n" ); document.write( "\n" ); document.write( "Nick's monthly car loan payment will be approximately $253.97.
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