document.write( "Question 1179262: Ten points in the plane are given, with no three collinear. Four
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document.write( "distinct segments joining pairs of these points are chosen at random, all such segments
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document.write( "being equally likely. The probability that some three of the segments form
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document.write( "a triangle whose vertices are among the ten given points is m/n, where m and n
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document.write( "are relatively prime positive integers. Find m + n. \n" );
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Algebra.Com's Answer #850248 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Let's break down this problem step-by-step:\r \n" ); document.write( "\n" ); document.write( "**1. Total Number of Segments:**\r \n" ); document.write( "\n" ); document.write( "* With 10 points, the number of segments that can be formed is given by the combination formula: \n" ); document.write( " * ¹⁰C₂ = 10! / (2! * 8!) = (10 * 9) / 2 = 45\r \n" ); document.write( "\n" ); document.write( "**2. Total Number of Ways to Choose 4 Segments:**\r \n" ); document.write( "\n" ); document.write( "* The number of ways to choose 4 segments from the 45 available is: \n" ); document.write( " * ⁴⁵C₄ = 45! / (4! * 41!) = (45 * 44 * 43 * 42) / (4 * 3 * 2 * 1) = 148,995\r \n" ); document.write( "\n" ); document.write( "**3. Number of Ways to Choose 4 Segments That DO NOT Form a Triangle:**\r \n" ); document.write( "\n" ); document.write( "To find the probability of forming a triangle, it's easier to find the probability of *not* forming a triangle and subtract that from 1.\r \n" ); document.write( "\n" ); document.write( "For 4 segments not to form a triangle, we need to consider the following cases:\r \n" ); document.write( "\n" ); document.write( "* **Case 1: No intersections.** All four segments are completely separate. \n" ); document.write( "* **Case 2: One intersection.** Two segments intersect at a point, but no triangle is formed. \n" ); document.write( "* **Case 3: Two intersections.** Two sets of intersecting segments, but no triangle is formed. \n" ); document.write( "* **Case 4: All 4 segments form a quadrilateral.**\r \n" ); document.write( "\n" ); document.write( "We will use the complementary counting method.\r \n" ); document.write( "\n" ); document.write( "Consider the cases where we *cannot* form a triangle:\r \n" ); document.write( "\n" ); document.write( "* **Case 1: All 4 segments are disjoint.** This is difficult to calculate directly. \n" ); document.write( "* **Case 2: Choose 4 segments such that no 3 form a triangle.**\r \n" ); document.write( "\n" ); document.write( "Instead, let's look at the complementary case:\r \n" ); document.write( "\n" ); document.write( "* **Case 1: 3 of the 4 segments form a triangle.** \n" ); document.write( " * Choose 3 points out of 10 to form a triangle: ¹⁰C₃ = 120 \n" ); document.write( " * Choose 1 remaining segment: 42 segments can be chosen that don't form a triangle with the previous 3. \n" ); document.write( " * So, 120 * 42 = 5040 ways to have 3 segments form a triangle, but we overcount, so we must divide by the number of times we can select the same triangle. \n" ); document.write( "* **Case 2: 4 segments form a complete quadrilateral.** \n" ); document.write( " * Choose 4 points out of 10: ¹⁰C₄ = 210 \n" ); document.write( " * Each set of 4 points forms 3 possible quadrilaterals. \n" ); document.write( " * 210 * 3 = 630 ways to have 4 segments form a quadrilateral.\r \n" ); document.write( "\n" ); document.write( "Let's use a different approach.\r \n" ); document.write( "\n" ); document.write( "We need to subtract the cases where we cannot form a triangle.\r \n" ); document.write( "\n" ); document.write( "* **Case 1: 4 disjoint segments.** \n" ); document.write( "* **Case 2: 2 pairs of disjoint segments.** \n" ); document.write( "* **Case 3: A \"path\" of 4 segments.** \n" ); document.write( "* **Case 4: A \"star\" with 4 segments.**\r \n" ); document.write( "\n" ); document.write( "Instead, let's find the number of ways to form a triangle.\r \n" ); document.write( "\n" ); document.write( "* Choose 3 points out of 10: ¹⁰C₃ = 120 \n" ); document.write( "* Choose 1 more segment from the remaining 42 segments: 42 \n" ); document.write( "* Total ways to have a triangle: 120 * 42 = 5040\r \n" ); document.write( "\n" ); document.write( "However, we are overcounting. \n" ); document.write( "We can select the 3 segments of the triangle from the chosen 4 segments in 4 ways.\r \n" ); document.write( "\n" ); document.write( "So we have to divide by 4.\r \n" ); document.write( "\n" ); document.write( "5040/4 = 1260\r \n" ); document.write( "\n" ); document.write( "So there are at least 1260 ways.\r \n" ); document.write( "\n" ); document.write( "Probability = 1260/148995 = 84/9933 = 28/3311.\r \n" ); document.write( "\n" ); document.write( "m=28, n=3311\r \n" ); document.write( "\n" ); document.write( "m+n = 3339\r \n" ); document.write( "\n" ); document.write( "**Final Answer:**\r \n" ); document.write( "\n" ); document.write( "m + n = 28 + 3311 = 3339 \n" ); document.write( " \n" ); document.write( " |