document.write( "Question 1179597: Formulate a simple geometric statement that can be proven using
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document.write( "any combination of the following: congruence axioms, substitution, and
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document.write( "definitions. Show two different ways to prove this statement. \n" );
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Algebra.Com's Answer #850209 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Okay, let's formulate a simple geometric statement and prove it in two different ways using congruence axioms, substitution, and definitions.\r \n" ); document.write( "\n" ); document.write( "**Geometric Statement:**\r \n" ); document.write( "\n" ); document.write( "**Given:** Two line segments AB and CD, where AB ≅ CD. Let E be a point on AB such that AE ≅ EB. Let F be a point on CD such that CF ≅ FD.\r \n" ); document.write( "\n" ); document.write( "**Prove:** AE ≅ CF.\r \n" ); document.write( "\n" ); document.write( "**Proof 1: Using Substitution and Congruence**\r \n" ); document.write( "\n" ); document.write( "| Statement | Reason | \n" ); document.write( "|---|---| \n" ); document.write( "| 1. AB ≅ CD | Given | \n" ); document.write( "| 2. AE ≅ EB | Given | \n" ); document.write( "| 3. CF ≅ FD | Given | \n" ); document.write( "| 4. AE = EB | Definition of congruent segments (If segments are congruent, their lengths are equal) | \n" ); document.write( "| 5. CF = FD | Definition of congruent segments | \n" ); document.write( "| 6. AB = CD | Definition of congruent segments | \n" ); document.write( "| 7. AE + EB = AB | Segment Addition Postulate | \n" ); document.write( "| 8. CF + FD = CD | Segment Addition Postulate | \n" ); document.write( "| 9. AE + AE = AB | Substitution (Substitute AE for EB in step 7) | \n" ); document.write( "| 10. CF + CF = CD | Substitution (Substitute CF for FD in step 8) | \n" ); document.write( "| 11. 2AE = AB | Simplification | \n" ); document.write( "| 12. 2CF = CD | Simplification | \n" ); document.write( "| 13. 2AE = CD | Substitution (Substitute CD for AB in step 11, using step 6) | \n" ); document.write( "| 14. 2AE = 2CF | Substitution (Substitute 2CF for CD in step 13, using step 12) | \n" ); document.write( "| 15. AE = CF | Division Property of Equality (Divide both sides by 2) | \n" ); document.write( "| 16. AE ≅ CF | Definition of congruent segments |\r \n" ); document.write( "\n" ); document.write( "**Proof 2: Using a Different Substitution Approach**\r \n" ); document.write( "\n" ); document.write( "| Statement | Reason | \n" ); document.write( "|---|---| \n" ); document.write( "| 1. AB ≅ CD | Given | \n" ); document.write( "| 2. AE ≅ EB | Given | \n" ); document.write( "| 3. CF ≅ FD | Given | \n" ); document.write( "| 4. AE = EB | Definition of congruent segments | \n" ); document.write( "| 5. CF = FD | Definition of congruent segments | \n" ); document.write( "| 6. AB = CD | Definition of congruent segments | \n" ); document.write( "| 7. AE + EB = AB | Segment Addition Postulate | \n" ); document.write( "| 8. CF + FD = CD | Segment Addition Postulate | \n" ); document.write( "| 9. AB/2 = AE | Division Property of Equality and Substitution(Using step 4, 7, and the fact that since AE=EB, AB is 2AE) | \n" ); document.write( "| 10. CD/2 = CF | Division Property of Equality and Substitution(Using step 5, 8, and the fact that since CF=FD, CD is 2CF) | \n" ); document.write( "| 11. AB/2 = CD/2 | Division Property of Equality (Dividing both sides of step 6 by 2) | \n" ); document.write( "| 12. AE = CD/2 | Substitution (Substitute AE for AB/2 in step 11, using step 9) | \n" ); document.write( "| 13. AE = CF | Substitution(Substitute CF for CD/2 in step 12, using step 10)| \n" ); document.write( "| 14. AE ≅ CF | Definition of congruent segments |\r \n" ); document.write( "\n" ); document.write( "**Explanation of the Proofs:**\r \n" ); document.write( "\n" ); document.write( "* Both proofs rely on the fundamental definitions of congruent segments, which state that if segments are congruent, their lengths are equal, and vice versa. \n" ); document.write( "* The Segment Addition Postulate is used to express the lengths of the given segments in terms of their parts. \n" ); document.write( "* The proofs then use substitution to manipulate the equations and arrive at the desired conclusion. \n" ); document.write( "* The division property of equality is used to isolate the segment lengths.\r \n" ); document.write( "\n" ); document.write( "These proofs are simple yet demonstrate the power of combining definitions, postulates, and substitution to prove geometric statements. \n" ); document.write( " \n" ); document.write( " |