document.write( "Question 1179878:  The daily temperature in February is normally distributed with a mean of 25 degrees and a standard deviation of 12 degrees. What percentage of the time will this temperature be:\r
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document.write( "A. above freezing? (32 degrees or more)\r
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document.write( "B. below zero?\r
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document.write( "c. between 35 degrees and 45 degrees?\r
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document.write( "Explain your answers.  \n" );
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| Algebra.Com's Answer #850160 by CPhill(1987)     You can put this solution on YOUR website! Let's solve each part of this problem step-by-step:\r \n" ); document.write( "\n" ); document.write( "Given:\r \n" ); document.write( "\n" ); document.write( "Mean (μ) = 25 degrees \n" ); document.write( "Standard deviation (σ) = 12 degrees \n" ); document.write( "Distribution: Normal \n" ); document.write( "A. Above Freezing (32 degrees or more):\r \n" ); document.write( "\n" ); document.write( "Calculate the z-score:\r \n" ); document.write( "\n" ); document.write( "z = (x - μ) / σ \n" ); document.write( "z = (32 - 25) / 12 \n" ); document.write( "z = 7 / 12 ≈ 0.58 \n" ); document.write( "Find the probability:\r \n" ); document.write( "\n" ); document.write( "We want P(X ≥ 32), which is the same as P(Z ≥ 0.58). \n" ); document.write( "Using a z-table or calculator, find P(Z < 0.58) ≈ 0.7190. \n" ); document.write( "P(Z ≥ 0.58) = 1 - P(Z < 0.58) = 1 - 0.7190 = 0.2810 \n" ); document.write( "Convert to percentage:\r \n" ); document.write( "\n" ); document.write( "0.2810 * 100% = 28.10% \n" ); document.write( "Explanation: There's about a 28.10% chance that the daily temperature will be above freezing (32 degrees or more).\r \n" ); document.write( "\n" ); document.write( "B. Below Zero:\r \n" ); document.write( "\n" ); document.write( "Calculate the z-score:\r \n" ); document.write( "\n" ); document.write( "z = (x - μ) / σ \n" ); document.write( "z = (0 - 25) / 12 \n" ); document.write( "z = -25 / 12 ≈ -2.08 \n" ); document.write( "Find the probability:\r \n" ); document.write( "\n" ); document.write( "We want P(X < 0), which is the same as P(Z < -2.08). \n" ); document.write( "Using a z-table or calculator, find P(Z < -2.08) ≈ 0.0188. \n" ); document.write( "Convert to percentage:\r \n" ); document.write( "\n" ); document.write( "0.0188 * 100% = 1.88% \n" ); document.write( "Explanation: There's about a 1.88% chance that the daily temperature will be below zero.\r \n" ); document.write( "\n" ); document.write( "C. Between 35 degrees and 45 degrees:\r \n" ); document.write( "\n" ); document.write( "Calculate the z-scores:\r \n" ); document.write( "\n" ); document.write( "For 35 degrees: \n" ); document.write( "z1 = (35 - 25) / 12 = 10 / 12 ≈ 0.83 \n" ); document.write( "For 45 degrees: \n" ); document.write( "z2 = (45 - 25) / 12 = 20 / 12 ≈ 1.67 \n" ); document.write( "Find the probability:\r \n" ); document.write( "\n" ); document.write( "We want P(35 ≤ X ≤ 45), which is the same as P(0.83 ≤ Z ≤ 1.67). \n" ); document.write( "P(0.83 ≤ Z ≤ 1.67) = P(Z ≤ 1.67) - P(Z ≤ 0.83) \n" ); document.write( "Using a z-table or calculator: \n" ); document.write( "P(Z ≤ 1.67) ≈ 0.9525 \n" ); document.write( "P(Z ≤ 0.83) ≈ 0.7967 \n" ); document.write( "P(0.83 ≤ Z ≤ 1.67) = 0.9525 - 0.7967 = 0.1558 \n" ); document.write( "Convert to percentage:\r \n" ); document.write( "\n" ); document.write( "0.1558 * 100% = 15.58% \n" ); document.write( "Explanation: There's about a 15.58% chance that the daily temperature will be between 35 and 45 degrees.\r \n" ); document.write( "\n" ); document.write( "Answers:\r \n" ); document.write( "\n" ); document.write( "A. 28.10% \n" ); document.write( "B. 1.88% \n" ); document.write( "C. 15.58% \n" ); document.write( " |