document.write( "Question 116943: Number problems. Find two consecutive positive integers such that the sum of their squares is 85. \n" ); document.write( "
Algebra.Com's Answer #85011 by ganesh(20)![]() ![]() ![]() You can put this solution on YOUR website! Let x and x +1 be two consecutive positive numbers.\r \n" ); document.write( "\n" ); document.write( "The square of the first number is x^2.\r \n" ); document.write( "\n" ); document.write( "The square of the second number is, (x+1)^2 = x^2 + 2x + 1.\r \n" ); document.write( "\n" ); document.write( "The sum of the squares of the two numbers = x^2 + x^2 + 2x + 1 \n" ); document.write( " = 2x^2 + 2x + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Given that, the sum of the squares is 85. \r \n" ); document.write( "\n" ); document.write( "Therefore, 2x^2 + 2x + 1 = 85.\r \n" ); document.write( "\n" ); document.write( "Or, 2x^2 + 2x - 84 = 0.\r \n" ); document.write( "\n" ); document.write( "Solve this quadratic equation. \r \n" ); document.write( "\n" ); document.write( "2x^2 + 14x -12x - 84 = 0\r \n" ); document.write( "\n" ); document.write( "2x (x +7) -12 (x +7) = 0\r \n" ); document.write( "\n" ); document.write( "(x + 7)(2x - 12) = 0\r \n" ); document.write( "\n" ); document.write( "x + 7 = 0 and 2x - 12 = 0\r \n" ); document.write( "\n" ); document.write( "x = -7 and x = 6.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since, x is given to be positive, it is 6.\r \n" ); document.write( "\n" ); document.write( "So, the required consecutive numbers are 6 and 7.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: 6^2 + 7^2 = 36 + 49 = 85.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Good luck! \n" ); document.write( " \n" ); document.write( " |