document.write( "Question 1181114: (a) An advertising company wants to estimate with 98% confidence interval, the number of times a website is hit during an hour. It is determined that = 26. How large a sample should the company take, if it wishes that the margin of error should not exceed 10? [04]
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document.write( "(b) If we take a sample from an infinite population, what will happen to the standard error of the mean when the sample size is increased from 60 to 240? \n" );
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Algebra.Com's Answer #850073 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! **(a) Sample size calculation:**\r \n" ); document.write( "\n" ); document.write( "1. **Identify the given information:**\r \n" ); document.write( "\n" ); document.write( "* Confidence level = 98% \n" ); document.write( "* Margin of error (E) = 10 \n" ); document.write( "* Population standard deviation (σ) = 26\r \n" ); document.write( "\n" ); document.write( "2. **Find the critical z-value:**\r \n" ); document.write( "\n" ); document.write( "For a 98% confidence level, α = 1 - 0.98 = 0.02. α/2 = 0.01. The critical z-value (z*) corresponding to 0.01 in the tail of the standard normal distribution is approximately 2.33.\r \n" ); document.write( "\n" ); document.write( "3. **Use the sample size formula:**\r \n" ); document.write( "\n" ); document.write( "n = (z* * σ / E)²\r \n" ); document.write( "\n" ); document.write( "4. **Plug in the values:**\r \n" ); document.write( "\n" ); document.write( "n = (2.33 * 26 / 10)² \n" ); document.write( "n = (60.58 / 10)² \n" ); document.write( "n = 6.058² \n" ); document.write( "n ≈ 36.7\r \n" ); document.write( "\n" ); document.write( "5. **Round up:** Since the sample size must be a whole number, always round up to the nearest integer. Therefore, the company should take a sample of at least 37.\r \n" ); document.write( "\n" ); document.write( "**(b) Effect of sample size on standard error:**\r \n" ); document.write( "\n" ); document.write( "The standard error of the mean (SEM) is calculated as:\r \n" ); document.write( "\n" ); document.write( "SEM = σ / √n\r \n" ); document.write( "\n" ); document.write( "Where:\r \n" ); document.write( "\n" ); document.write( "* σ = population standard deviation \n" ); document.write( "* n = sample size\r \n" ); document.write( "\n" ); document.write( "If the sample size is increased from n₁ = 60 to n₂ = 240, let's see what happens to the SEM.\r \n" ); document.write( "\n" ); document.write( "* Initial SEM (SEM₁) = σ / √60 \n" ); document.write( "* New SEM (SEM₂) = σ / √240\r \n" ); document.write( "\n" ); document.write( "We can rewrite √240 as √(4 * 60) = 2√60\r \n" ); document.write( "\n" ); document.write( "So, SEM₂ = σ / (2√60) = (1/2) * (σ / √60) = (1/2) * SEM₁\r \n" ); document.write( "\n" ); document.write( "Therefore, when the sample size is increased from 60 to 240 (a four-fold increase), the standard error of the mean is *halved*. \n" ); document.write( " \n" ); document.write( " |