document.write( "Question 1181389: At the Foremost State Bank the average savings account balance in 2012 was $1100. A random sample of 38 savings account balanes for 2013 yielded a mean of $1800 with a standard deviation of $2800. At the α = 0.10 significance level test the claim that the mean savings account balance in 2013 is different from the mean savings account balance in 2012.\r
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document.write( "(a) Identify the correct alternative hypothesis.\r
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document.write( "μ _____ $1100\r
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document.write( "(b) The test statistic value is __________. (Round your answer to two decimal places.)\r
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document.write( "(c) Using the critical value approach (traditional method), the critical value is ____________ . (Round your answer to three decimal places.)\r
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document.write( "(d) Based on your answers above, do you
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document.write( "Reject the H^0
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document.write( "Fail to reject the H^0
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document.write( "(e) Explain your decision about the claim. \n" );
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Algebra.Com's Answer #850037 by CPhill(1987) You can put this solution on YOUR website! Here's a breakdown of the solution:\r \n" ); document.write( "\n" ); document.write( "**(a) Alternative Hypothesis:**\r \n" ); document.write( "\n" ); document.write( "The claim is that the mean savings account balance in 2013 is *different* from the mean savings account balance in 2012. \"Different\" means *not equal to*. Therefore, the correct alternative hypothesis is:\r \n" ); document.write( "\n" ); document.write( "μ **≠** $1100\r \n" ); document.write( "\n" ); document.write( "**(b) Test Statistic:**\r \n" ); document.write( "\n" ); document.write( "We are given:\r \n" ); document.write( "\n" ); document.write( "* Sample mean (x̄) = $1800 \n" ); document.write( "* Population mean (μ) = $1100 \n" ); document.write( "* Sample size (n) = 38 \n" ); document.write( "* Sample standard deviation (s) = $2800\r \n" ); document.write( "\n" ); document.write( "Since the sample size is greater than 30, we use a t-test. The test statistic is:\r \n" ); document.write( "\n" ); document.write( "t = (x̄ - μ) / (s / √n) \n" ); document.write( "t = (1800 - 1100) / (2800 / √38) \n" ); document.write( "t = 700 / (2800 / 6.1644) \n" ); document.write( "t = 700 / 454.16 \n" ); document.write( "t ≈ 1.54\r \n" ); document.write( "\n" ); document.write( "The test statistic value is approximately **1.54**.\r \n" ); document.write( "\n" ); document.write( "**(c) Critical Value:**\r \n" ); document.write( "\n" ); document.write( "We're using a two-tailed test (because H₁ is ≠) with α = 0.10. Degrees of freedom (df) = n - 1 = 38 - 1 = 37.\r \n" ); document.write( "\n" ); document.write( "For a two-tailed test with α = 0.10 and df = 37, you'd consult a t-table or calculator. You're looking for the t-value that cuts off 0.05 in *each* tail (since it's two-tailed).\r \n" ); document.write( "\n" ); document.write( "The critical values are approximately **±1.687**.\r \n" ); document.write( "\n" ); document.write( "**(d) Decision:**\r \n" ); document.write( "\n" ); document.write( "Our test statistic (1.54) falls *between* -1.687 and +1.687. It's *not* in the rejection region (the tails). Therefore, we *fail to reject* the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**Fail to reject the H₀**\r \n" ); document.write( "\n" ); document.write( "**(e) Explanation:**\r \n" ); document.write( "\n" ); document.write( "Because our calculated test statistic (1.54) falls within the non-rejection region (between the critical values), we do not have sufficient evidence at the α = 0.10 significance level to reject the null hypothesis. In simpler terms, even though the sample mean is higher ($1800 vs $1100), there's too much variability in the sample (indicated by the large standard deviation) to confidently say that the true population mean for 2013 is *different* from $1100. The difference we see in the sample could reasonably be due to random chance. \n" ); document.write( " \n" ); document.write( " |