document.write( "Question 116890: Solve.\r
\n" ); document.write( "\n" ); document.write( "The combined resistance of two resistors r1 and r2 in a parallel circuit is given by the formula rt= 1 OVER 1/r1 + 1/r2. Simplify the formula.
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Algebra.Com's Answer #85002 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"r%5Bt%5D+=+1%2F%281%2Fr%5B1%5D+%2B+1%2Fr%5B2%5D%29\"
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\n" ); document.write( "This is not the way this formula is usually written, but it is correct.
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\n" ); document.write( "You can simplify this by multiplying the right side by \"%28r%5B1%5D%2Ar%5B2%5D%29%2F%28r%5B1%5D%2Ar%5B2%5D%29\"
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\n" ); document.write( "Since the numerator of this multiplier is equal to the denominator, this is the same as
\n" ); document.write( "multiplying the right side by 1. This means that this multiplication doesn't change the
\n" ); document.write( "value of the right side.
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\n" ); document.write( "The multiplication leads to:
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\n" ); document.write( "A little difficult to see, maybe, but the very top \"1\" gets multiplied by \"r%5B1%5D%2Ar%5B2%5D\" and in
\n" ); document.write( "the denominator the numerators of the two fractions (both numerators are \"1\") also get multiplied
\n" ); document.write( "by \"r%5B1%5D%2Ar%5B2%5D\". This changes the equation to:
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\n" ); document.write( "In this, in the three places where a \"1\" is a multiplier, you can simplify the work by just
\n" ); document.write( "erasing the \"1\". This simplifies the equation to:
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\n" ); document.write( "Then in the fractions in the denominator you can cancel the denominator of the fraction with
\n" ); document.write( "the corresponding term in the numerator of the fraction as follows:
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\n" ); document.write( "Note that the cancellations shown reduce the equation to:
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\n" ); document.write( "\"r%5Bt%5D+=+r%5B1%5D%2Ar%5B2%5D%2F%28r%5B2%5D+%2B+r%5B1%5D%29\"
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\n" ); document.write( "or by simply reversing the order of the terms in the denominator, which changes nothing, you
\n" ); document.write( "get the more familiar form:
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\n" ); document.write( "\n" ); document.write( "\"r%5Bt%5D+=+r%5B1%5D%2Ar%5B2%5D%2F%28r%5B1%5D+%2B+r%5B2%5D%29\"
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\n" ); document.write( "This is the answer to the problem. It shows that two resistors connected in parallel can
\n" ); document.write( "be replaced by a single resistor \"r%5Bt%5D\" whose value is equal to the product of the two
\n" ); document.write( "resistors divided by the sum of the two resistors.
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\n" ); document.write( "Regarding my comment above, this problem does not list the formula for \"r%5Bt%5D\" the way that it
\n" ); document.write( "is usually written. The way it is usually given is:
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\n" ); document.write( "\"1%2Fr%5Bt%5D+=+1%2Fr%5B1%5D+%2B+1%2Fr%5B2%5D\"
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\n" ); document.write( "If you solve this equation for \"r%5Bt%5D\" you will get the same answer that we got for this problem ...
\n" ); document.write( "namely you will again get:
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\n" ); document.write( "\"r%5Bt%5D+=+r%5B1%5D%2Ar%5B2%5D%2F%28r%5B1%5D+%2B+r%5B2%5D%29\"
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\n" ); document.write( "Hope this helps you to understand the problem and how to solve it.
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