document.write( "Question 116908: Betty and Frank, working together can paint the exterior of a house in 3 days. Frank, by himself can complete the job in 8 days less than Betty. How long will it take Betty to complete the job by herself? \n" ); document.write( "
Algebra.Com's Answer #85000 by edjones(8007)\"\" \"About 
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Betty can paint a house in b days.
\n" ); document.write( "Frank can paint a house in (b-8) days.
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\n" ); document.write( "1/b is the amt of the job betty can do in 1 day.
\n" ); document.write( "1/(b-8) is the amt of the job Frank can do in 1 day.
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\n" ); document.write( "1/b+ 1/(b-8)=1/3
\n" ); document.write( "3(b-8)+3b=b(b-8) Multiply each side by 3b(b-8) to eliminate fractions.
\n" ); document.write( "3b-24+3b=b^2-8b
\n" ); document.write( "b^2-14b+24=0
\n" ); document.write( "(b-2)(b-12)=0
\n" ); document.write( "b=2, b=12 since Frank can do the job 8 days sooner than Betty b=2 is not an answer.
\n" ); document.write( "b=12 days, f=4 days
\n" ); document.write( "Check:
\n" ); document.write( "1/12+ 1/4 =1/3
\n" ); document.write( "1/12+ 3/12= 4/12 True.
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