document.write( "Question 116908: Betty and Frank, working together can paint the exterior of a house in 3 days. Frank, by himself can complete the job in 8 days less than Betty. How long will it take Betty to complete the job by herself? \n" ); document.write( "
Algebra.Com's Answer #85000 by edjones(8007)![]() ![]() You can put this solution on YOUR website! Betty can paint a house in b days. \n" ); document.write( "Frank can paint a house in (b-8) days. \n" ); document.write( ". \n" ); document.write( "1/b is the amt of the job betty can do in 1 day. \n" ); document.write( "1/(b-8) is the amt of the job Frank can do in 1 day. \n" ); document.write( ". \n" ); document.write( "1/b+ 1/(b-8)=1/3 \n" ); document.write( "3(b-8)+3b=b(b-8) Multiply each side by 3b(b-8) to eliminate fractions. \n" ); document.write( "3b-24+3b=b^2-8b \n" ); document.write( "b^2-14b+24=0 \n" ); document.write( "(b-2)(b-12)=0 \n" ); document.write( "b=2, b=12 since Frank can do the job 8 days sooner than Betty b=2 is not an answer. \n" ); document.write( "b=12 days, f=4 days \n" ); document.write( "Check: \n" ); document.write( "1/12+ 1/4 =1/3 \n" ); document.write( "1/12+ 3/12= 4/12 True. \n" ); document.write( ". \n" ); document.write( "Ed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |