document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1209708>Question 1209708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "The average usage of water is 4000 litres per month. During the  months of May June and July the usage is 4500 litres per month. What should the average usage of water be for the rest of the months so that the total consumption for the year is the same. \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #849951 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=849951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "In the three months of May, June, and July, water usage was 4500-4000 = 500 litres over the average each month making a total of 3*500 = 1500 litres over the average.<br><BR>\n" );
document.write( "For the overall average for the whole year to be 4000 litres per month, the total consumption in the other 9 months must be 1500 litres under the average.<br><BR>\n" );
document.write( "1500 litres under the average, distributed evenly over the 9 months, means monthly consumption is 1500/9 = 500/3 = 166 2/3 liters under the monthly average of 4000 litres.<br><BR>\n" );
document.write( "ANSWER: 4000 - 166 2/3 = 3833 1/3 litres per month<br><BR>\n" );
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