document.write( "Question 1182170: The final grades of students in Foreign Language are normally distributed. records show that the average grade of students is 85 with the standard deviation of 2.3; suppose the professor wants to convert the grades of the students into an alpha-grade; A as the highest and D as the lowest grades, and DECIDES to assign: 10% A's, 20% B's, 30% C's, and 40% D's. What shall be the cut-off grades of these grade ranges? \n" ); document.write( "
Algebra.Com's Answer #849943 by CPhill(1959)\"\" \"About 
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Here's how to determine the cut-off grades for the Foreign Language class:\r
\n" ); document.write( "\n" ); document.write( "**Understanding the Problem**\r
\n" ); document.write( "\n" ); document.write( "The professor wants to assign letter grades based on a normal distribution. This means we need to find the scores that correspond to the given percentages of each grade.\r
\n" ); document.write( "\n" ); document.write( "**Steps**\r
\n" ); document.write( "\n" ); document.write( "1. **Percentiles:** We'll use the given percentages to find the corresponding percentiles in the normal distribution.
\n" ); document.write( " * 10% A's: This means the top 10% of scores are A's. So, the cutoff for a B is at the 90th percentile.
\n" ); document.write( " * 20% B's: The cutoff for a C is at the 70th percentile (90th percentile - 20%).
\n" ); document.write( " * 30% C's: The cutoff for a D is at the 40th percentile (70th percentile - 30%).\r
\n" ); document.write( "\n" ); document.write( "2. **Z-scores:** We need to find the z-scores that correspond to these percentiles. A z-score tells us how many standard deviations a score is away from the mean. You can use a z-table or a calculator with statistical functions to find these z-scores.
\n" ); document.write( " * 90th percentile: z ≈ 1.28
\n" ); document.write( " * 70th percentile: z ≈ 0.52
\n" ); document.write( " * 40th percentile: z ≈ -0.25\r
\n" ); document.write( "\n" ); document.write( "3. **Cut-off Scores:** Now, use the z-scores, the mean (85), and the standard deviation (2.3) to calculate the cut-off scores:
\n" ); document.write( " * B cutoff (90th percentile): Score = Mean + (z-score * Standard Deviation) = 85 + (1.28 * 2.3) ≈ 87.94
\n" ); document.write( " * C cutoff (70th percentile): Score = 85 + (0.52 * 2.3) ≈ 86.20
\n" ); document.write( " * D cutoff (40th percentile): Score = 85 + (-0.25 * 2.3) ≈ 84.43\r
\n" ); document.write( "\n" ); document.write( "**Results**\r
\n" ); document.write( "\n" ); document.write( "* **A:** 87.94 and above
\n" ); document.write( "* **B:** Between 86.20 and 87.94
\n" ); document.write( "* **C:** Between 84.43 and 86.20
\n" ); document.write( "* **D:** Below 84.43
\n" ); document.write( "
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