document.write( "Question 1182694: c) A manufacturer of machine parts is considering buying one of the three machines currently in the market. The following is their daily output for five different days;
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document.write( "machine
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document.write( "A B C
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document.write( "25 31 24
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document.write( "30 39 30
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document.write( "36 38 28
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document.write( "38 42 25
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document.write( "31 35 28\r
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document.write( "Do the machines have equal output rate? Test at α=0.05 (10 marks)\r
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Algebra.Com's Answer #849909 by CPhill(1987) You can put this solution on YOUR website! Here's how to determine if the machines have equal output rates using an ANOVA test:\r \n" ); document.write( "\n" ); document.write( "**1. State the Hypotheses:**\r \n" ); document.write( "\n" ); document.write( "* **Null Hypothesis (H0):** The machines have equal output rates (μA = μB = μC). \n" ); document.write( "* **Alternative Hypothesis (H1):** At least one machine has a different output rate.\r \n" ); document.write( "\n" ); document.write( "**2. Significance Level:** α = 0.05\r \n" ); document.write( "\n" ); document.write( "**3. Calculate the Sum of Squares:**\r \n" ); document.write( "\n" ); document.write( "We need to calculate the Sum of Squares Between Groups (SSB) and the Sum of Squares Within Groups (SSW).\r \n" ); document.write( "\n" ); document.write( "* **Calculate the Grand Mean:** \n" ); document.write( " Grand Mean = (Sum of all observations) / (Total number of observations) \n" ); document.write( " Grand Mean = (25+30+36+38+31 + 31+39+38+42+35 + 24+30+28+25+28) / 15 \n" ); document.write( " Grand Mean = 480 / 15 = 32\r \n" ); document.write( "\n" ); document.write( "* **Calculate SSB:** \n" ); document.write( " SSB = 5 * (Mean_A - Grand_Mean)² + 5 * (Mean_B - Grand_Mean)² + 5 * (Mean_C - Grand_Mean)²\r \n" ); document.write( "\n" ); document.write( " * Mean_A = (25+30+36+38+31)/5 = 32 \n" ); document.write( " * Mean_B = (31+39+38+42+35)/5 = 37 \n" ); document.write( " * Mean_C = (24+30+28+25+28)/5 = 27\r \n" ); document.write( "\n" ); document.write( " SSB = 5 * (32 - 32)² + 5 * (37 - 32)² + 5 * (27 - 32)² \n" ); document.write( " SSB = 0 + 5 * 25 + 5 * 25 \n" ); document.write( " SSB = 250\r \n" ); document.write( "\n" ); document.write( "* **Calculate SSW:**\r \n" ); document.write( "\n" ); document.write( " SSW = Σ(each observation - its group mean)² \n" ); document.write( " SSW = (25-32)² + (30-32)² + ... + (28-27)² (add up the squared differences for all 15 observations) \n" ); document.write( " SSW = 49 + 4 + 16 + 36 + 1 + 1 + 49 + 36 + 100 + 9 + 4 + 4 + 1 + 9 + 1 \n" ); document.write( " SSW = 310\r \n" ); document.write( "\n" ); document.write( "* **Calculate SST (Total Sum of Squares):** SST = SSW + SSB = 310+250 = 560\r \n" ); document.write( "\n" ); document.write( "**4. Degrees of Freedom:**\r \n" ); document.write( "\n" ); document.write( "* df_between (degrees of freedom between groups) = Number of groups - 1 = 3 - 1 = 2 \n" ); document.write( "* df_within (degrees of freedom within groups) = Total number of observations - Number of groups = 15 - 3 = 12 \n" ); document.write( "* df_total = n-1 = 15-1 = 14\r \n" ); document.write( "\n" ); document.write( "**5. Calculate Mean Square:**\r \n" ); document.write( "\n" ); document.write( "* MSB (Mean Square Between) = SSB / df_between = 250 / 2 = 125 \n" ); document.write( "* MSW (Mean Square Within) = SSW / df_within = 310 / 12 ≈ 25.83\r \n" ); document.write( "\n" ); document.write( "**6. Calculate the F-statistic:**\r \n" ); document.write( "\n" ); document.write( "F = MSB / MSW = 125 / 25.83 ≈ 4.84\r \n" ); document.write( "\n" ); document.write( "**7. Determine the Critical Value:**\r \n" ); document.write( "\n" ); document.write( "Using an F-distribution table with α = 0.05, df_between = 2, and df_within = 12, the critical F-value is approximately 3.89.\r \n" ); document.write( "\n" ); document.write( "**8. Decision:**\r \n" ); document.write( "\n" ); document.write( "Our calculated F-statistic (4.84) is *greater than* the critical value (3.89). Therefore, we *reject* the null hypothesis.\r \n" ); document.write( "\n" ); document.write( "**9. Conclusion:**\r \n" ); document.write( "\n" ); document.write( "At the 5% level of significance, there *is* sufficient evidence to conclude that the machines do *not* have equal output rates. At least one machine has a different output rate. \n" ); document.write( " \n" ); document.write( " |