document.write( "Question 1184022: An insurance policy is written to cover a loss, X, where X has a uniform distribution on
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document.write( "[0, 1000]. At what level must a deductible be set in order for the expected payment to be
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document.write( "25% of what it would be with no deductible? \n" );
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Algebra.Com's Answer #849886 by CPhill(1987)![]() ![]() You can put this solution on YOUR website! Here's how to determine the deductible level:\r \n" ); document.write( "\n" ); document.write( "**1. Expected Payment with No Deductible:**\r \n" ); document.write( "\n" ); document.write( "If there's no deductible, the expected payment is simply the expected value of the loss X. For a uniform distribution on [a, b], the expected value is (a+b)/2. In this case, a = 0 and b = 1000, so:\r \n" ); document.write( "\n" ); document.write( "E[X] = (0 + 1000) / 2 = 500\r \n" ); document.write( "\n" ); document.write( "**2. Desired Expected Payment:**\r \n" ); document.write( "\n" ); document.write( "The problem states that the expected payment with the deductible should be 25% of the expected payment with no deductible:\r \n" ); document.write( "\n" ); document.write( "Desired Expected Payment = 0.25 * 500 = 125\r \n" ); document.write( "\n" ); document.write( "**3. Expected Payment with a Deductible:**\r \n" ); document.write( "\n" ); document.write( "Let 'd' be the deductible. The payment Y made by the insurance company is:\r \n" ); document.write( "\n" ); document.write( "* Y = 0, if X ≤ d \n" ); document.write( "* Y = X - d, if X > d\r \n" ); document.write( "\n" ); document.write( "The expected payment with the deductible is:\r \n" ); document.write( "\n" ); document.write( "E[Y] = ∫ (x - d) * f(x) dx (integrated from d to 1000)\r \n" ); document.write( "\n" ); document.write( "Where f(x) is the probability density function of the uniform distribution, which is 1/(1000 - 0) = 1/1000 for 0 ≤ x ≤ 1000.\r \n" ); document.write( "\n" ); document.write( "So,\r \n" ); document.write( "\n" ); document.write( "E[Y] = ∫ (x - d) * (1/1000) dx (integrated from d to 1000) \n" ); document.write( "E[Y] = (1/1000) * [x²/2 - dx] (evaluated from d to 1000) \n" ); document.write( "E[Y] = (1/1000) * [(1000²/2 - 1000d) - (d²/2 - d²)] \n" ); document.write( "E[Y] = (1/1000) * [500000 - 1000d - d²/2 + d²] \n" ); document.write( "E[Y] = (1/1000) * [500000 - 1000d + d²/2] \n" ); document.write( "E[Y] = 500 - d + d²/2000\r \n" ); document.write( "\n" ); document.write( "**4. Solve for the Deductible (d):**\r \n" ); document.write( "\n" ); document.write( "We want E[Y] to equal 125:\r \n" ); document.write( "\n" ); document.write( "125 = 500 - d + d²/2000 \n" ); document.write( "0 = 375 - d + d²/2000\r \n" ); document.write( "\n" ); document.write( "Multiply by 2000 to get rid of the fraction:\r \n" ); document.write( "\n" ); document.write( "0 = 750000 - 2000d + d²\r \n" ); document.write( "\n" ); document.write( "This is a quadratic equation. Rearrange it into standard form:\r \n" ); document.write( "\n" ); document.write( "d² - 2000d + 750000 = 0\r \n" ); document.write( "\n" ); document.write( "Use the quadratic formula to solve for d:\r \n" ); document.write( "\n" ); document.write( "d = (-b ± √(b² - 4ac)) / 2a \n" ); document.write( "d = (2000 ± √((-2000)² - 4 * 1 * 750000)) / 2 \n" ); document.write( "d = (2000 ± √(4000000 - 3000000)) / 2 \n" ); document.write( "d = (2000 ± √1000000) / 2 \n" ); document.write( "d = (2000 ± 1000) / 2\r \n" ); document.write( "\n" ); document.write( "This gives us two possible solutions for d:\r \n" ); document.write( "\n" ); document.write( "* d = (2000 + 1000) / 2 = 1500 \n" ); document.write( "* d = (2000 - 1000) / 2 = 500\r \n" ); document.write( "\n" ); document.write( "Since the deductible cannot be greater than the maximum possible loss (1000), the correct solution is:\r \n" ); document.write( "\n" ); document.write( "d = 500\r \n" ); document.write( "\n" ); document.write( "**Answer:** The deductible must be set at 500. \n" ); document.write( " \n" ); document.write( " |