document.write( "Question 1184068: In investing $5,650 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest. The rest was invested in a riskier mini-mall development plan paying 10% annual simple interest. The combined interest earned for the first year was $445. How much money was invested at each rate?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #849881 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Here's how to solve this problem:\r \n" ); document.write( "\n" ); document.write( "**Let:**\r \n" ); document.write( "\n" ); document.write( "* 'x' be the amount invested in the savings account at 4% interest. \n" ); document.write( "* 'y' be the amount invested in the mini-mall development at 10% interest.\r \n" ); document.write( "\n" ); document.write( "**Set up the equations:**\r \n" ); document.write( "\n" ); document.write( "* **Equation 1 (Total investment):** x + y = 5650 \n" ); document.write( "* **Equation 2 (Total interest):** 0.04x + 0.10y = 445\r \n" ); document.write( "\n" ); document.write( "**Solve the equations:**\r \n" ); document.write( "\n" ); document.write( "One way to solve this is using substitution:\r \n" ); document.write( "\n" ); document.write( "1. **Solve Equation 1 for x:** x = 5650 - y\r \n" ); document.write( "\n" ); document.write( "2. **Substitute this value of x into Equation 2:** \n" ); document.write( " 0.04(5650 - y) + 0.10y = 445\r \n" ); document.write( "\n" ); document.write( "3. **Simplify and solve for y:** \n" ); document.write( " 226 - 0.04y + 0.10y = 445 \n" ); document.write( " 0.06y = 219 \n" ); document.write( " y = 3650\r \n" ); document.write( "\n" ); document.write( "4. **Substitute the value of y back into Equation 1 to find x:** \n" ); document.write( " x + 3650 = 5650 \n" ); document.write( " x = 2000\r \n" ); document.write( "\n" ); document.write( "**Answer:**\r \n" ); document.write( "\n" ); document.write( "* $2000 was invested in the savings account at 4% interest. \n" ); document.write( "* $3650 was invested in the mini-mall development at 10% interest. \n" ); document.write( " \n" ); document.write( " |