document.write( "Question 1184145: The table below shows the number of mangoes and cashew of the
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document.write( "same size in a bag. If two of the fruits are picked at random, one at a
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document.write( "time without replacement, find the probability that:
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document.write( "a. Both are good fruits b. Both are bad fruits
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document.write( "c. One is a good cashew and the other bad mango.
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document.write( " Mangoes Cashews Total
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document.write( "Good 10 6 18
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document.write( "Bad 6 8 12
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document.write( "Total 16 14 30 \n" );
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Algebra.Com's Answer #849875 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Here's how to calculate the probabilities:\r \n" ); document.write( "\n" ); document.write( "**a. Both are good fruits:**\r \n" ); document.write( "\n" ); document.write( "* **First pick:** There are 18 good fruits out of a total of 30 fruits. The probability of picking a good fruit first is 18/30. \n" ); document.write( "* **Second pick:** After picking one good fruit, there are now 17 good fruits left and a total of 29 fruits. The probability of picking another good fruit is 17/29. \n" ); document.write( "* **Probability of both good:** Multiply the probabilities of each pick: (18/30) * (17/29) = 306/870 = 51/145 ≈ 0.3517\r \n" ); document.write( "\n" ); document.write( "**b. Both are bad fruits:**\r \n" ); document.write( "\n" ); document.write( "* **First pick:** There are 12 bad fruits out of 30 total fruits. The probability of picking a bad fruit first is 12/30. \n" ); document.write( "* **Second pick:** After picking one bad fruit, there are 11 bad fruits left and 29 total fruits. The probability of picking another bad fruit is 11/29. \n" ); document.write( "* **Probability of both bad:** Multiply the probabilities: (12/30) * (11/29) = 132/870 = 22/145 ≈ 0.1517\r \n" ); document.write( "\n" ); document.write( "**c. One is a good cashew and the other a bad mango:**\r \n" ); document.write( "\n" ); document.write( "There are two ways this can happen: good cashew then bad mango, or bad mango then good cashew. We have to calculate the probability of each case and then add them together.\r \n" ); document.write( "\n" ); document.write( "* **Good cashew then bad mango:** \n" ); document.write( " * Probability of good cashew first: 6/30 \n" ); document.write( " * Probability of bad mango second: 6/29 \n" ); document.write( " * Combined probability: (6/30) * (6/29) = 36/870 = 6/145 ≈ 0.0414\r \n" ); document.write( "\n" ); document.write( "* **Bad mango then good cashew:** \n" ); document.write( " * Probability of bad mango first: 6/30 \n" ); document.write( " * Probability of good cashew second: 6/29 \n" ); document.write( " * Combined probability: (6/30) * (6/29) = 36/870 = 6/145 ≈ 0.0414\r \n" ); document.write( "\n" ); document.write( "* **Total probability:** Add the probabilities of the two scenarios: (6/145) + (6/145) = 12/145 ≈ 0.0828 \n" ); document.write( " \n" ); document.write( " |