document.write( "Question 1184193: 9x^2+72x-128y+80=0 \n" ); document.write( "
Algebra.Com's Answer #849872 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! To solve for y in the equation 9x² + 72x - 128y + 80 = 0, we need to isolate y on one side of the equation. Here's how:\r \n" ); document.write( "\n" ); document.write( "1. **Move the terms without y to the other side:** \n" ); document.write( " Subtract 9x² and 72x and 80 from both sides of the equation: \n" ); document.write( " -128y = -9x² - 72x - 80\r \n" ); document.write( "\n" ); document.write( "2. **Divide by -128 to solve for y:** \n" ); document.write( " y = (-9x² - 72x - 80) / -128\r \n" ); document.write( "\n" ); document.write( "3. **Simplify (optional):** \n" ); document.write( " You can simplify the equation by dividing each term in the numerator by -128: \n" ); document.write( " y = (9/128)x² + (72/128)x + (80/128) \n" ); document.write( " y = (9/128)x² + (9/16)x + (5/8)\r \n" ); document.write( "\n" ); document.write( "Therefore, the solution for y is: \n" ); document.write( "y = (9/128)x² + (9/16)x + (5/8) \n" ); document.write( "or \n" ); document.write( "y = (9x² + 72x + 80) / 128 \n" ); document.write( " \n" ); document.write( " |