document.write( "Question 1184193: 9x^2+72x-128y+80=0 \n" ); document.write( "
Algebra.Com's Answer #849872 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
To solve for y in the equation 9x² + 72x - 128y + 80 = 0, we need to isolate y on one side of the equation. Here's how:\r
\n" ); document.write( "\n" ); document.write( "1. **Move the terms without y to the other side:**
\n" ); document.write( " Subtract 9x² and 72x and 80 from both sides of the equation:
\n" ); document.write( " -128y = -9x² - 72x - 80\r
\n" ); document.write( "\n" ); document.write( "2. **Divide by -128 to solve for y:**
\n" ); document.write( " y = (-9x² - 72x - 80) / -128\r
\n" ); document.write( "\n" ); document.write( "3. **Simplify (optional):**
\n" ); document.write( " You can simplify the equation by dividing each term in the numerator by -128:
\n" ); document.write( " y = (9/128)x² + (72/128)x + (80/128)
\n" ); document.write( " y = (9/128)x² + (9/16)x + (5/8)\r
\n" ); document.write( "\n" ); document.write( "Therefore, the solution for y is:
\n" ); document.write( "y = (9/128)x² + (9/16)x + (5/8)
\n" ); document.write( "or
\n" ); document.write( "y = (9x² + 72x + 80) / 128
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