document.write( "Question 1209693: What is the remainder when the polynomial
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document.write( "g(x) = x^3 - 14x^2 - 67x - 90 + 5x^3 - 20x^2 + 7x - 135
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document.write( "is divided by x - 1?
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Algebra.Com's Answer #849825 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! To find the remainder when g(x) is divided by x - 1, we can use the Remainder Theorem. The Remainder Theorem states that if we divide a polynomial g(x) by (x - c), the remainder is g(c). In this case, we are dividing by x - 1, so c = 1.\r \n" ); document.write( "\n" ); document.write( "First, let's simplify g(x) by combining like terms: \n" ); document.write( "g(x) = (x^3 + 5x^3) + (-14x^2 - 20x^2) + (-67x + 7x) + (-90 - 135) \n" ); document.write( "g(x) = 6x^3 - 34x^2 - 60x - 225\r \n" ); document.write( "\n" ); document.write( "Now, we need to find g(1): \n" ); document.write( "g(1) = 6(1)^3 - 34(1)^2 - 60(1) - 225 \n" ); document.write( "g(1) = 6 - 34 - 60 - 225 \n" ); document.write( "g(1) = -313\r \n" ); document.write( "\n" ); document.write( "Therefore, the remainder when g(x) is divided by x - 1 is -313.\r \n" ); document.write( "\n" ); document.write( "Final Answer: The final answer is $\boxed{-313}$ \n" ); document.write( " \n" ); document.write( " |