document.write( "Question 116850: \r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "Thanks so much!
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Algebra.Com's Answer #84981 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
L=2W+10
\n" ); document.write( "32=2(2W+10)+2W
\n" ); document.write( "32=4W+20+2W
\n" ); document.write( "32=6W+20
\n" ); document.write( "6W=32-20
\n" ); document.write( "6W=12
\n" ); document.write( "W=12/6
\n" ); document.write( "W=2 ANSWER FOR THE WIDTH.
\n" ); document.write( "L=2*2+10
\n" ); document.write( "L=4+10
\n" ); document.write( "L=14 ANSWER FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*2+2*14=32
\n" ); document.write( "4+28=32
\n" ); document.write( "32=32
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