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document.write( "The length of a rectangle is 10 in. more than twice its width. If the perimeter of the rectangle is 32 in., find the width of the rectangle.\r
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document.write( "Thanks so much! \n" );
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Algebra.Com's Answer #84981 by checkley71(8403)![]() ![]() ![]() You can put this solution on YOUR website! L=2W+10 \n" ); document.write( "32=2(2W+10)+2W \n" ); document.write( "32=4W+20+2W \n" ); document.write( "32=6W+20 \n" ); document.write( "6W=32-20 \n" ); document.write( "6W=12 \n" ); document.write( "W=12/6 \n" ); document.write( "W=2 ANSWER FOR THE WIDTH. \n" ); document.write( "L=2*2+10 \n" ); document.write( "L=4+10 \n" ); document.write( "L=14 ANSWER FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "2*2+2*14=32 \n" ); document.write( "4+28=32 \n" ); document.write( "32=32 \n" ); document.write( " |