document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1185383>Question 1185383</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The design costs of an advertisement in a glossy magazine are £9000 and the cost per cm2 of print is <BR>\n" );
document.write( "£50.<BR>\n" );
document.write( "a. Write an expression for the total cost of publishing an advert which covers x cm2<BR>\n" );
document.write( "b. The advertising budget is between £10,800 and £12,500. Write down and solve an inequality to <BR>\n" );
document.write( "work out the minimum and maximum area that could be used. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #849753 by </B><A HREF=/tutors/aboutme.mpl?userid=CPhill><B>CPhill(1959)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CPhill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=CPhill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=849753\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> **a.** Let 'C' be the total cost and 'x' be the area in cm². The expression for the total cost is:\r<BR>\n" );
document.write( "\n" );
document.write( "C = 9000 + 50x\r<BR>\n" );
document.write( "\n" );
document.write( "**b.** The advertising budget is between £10,800 and £12,500. So, the inequality is:\r<BR>\n" );
document.write( "\n" );
document.write( "10800 ≤ C ≤ 12500\r<BR>\n" );
document.write( "\n" );
document.write( "Substitute the expression for C:\r<BR>\n" );
document.write( "\n" );
document.write( "10800 ≤ 9000 + 50x ≤ 12500\r<BR>\n" );
document.write( "\n" );
document.write( "Subtract 9000 from all parts of the inequality:\r<BR>\n" );
document.write( "\n" );
document.write( "10800 - 9000 ≤ 50x ≤ 12500 - 9000<BR>\n" );
document.write( "1800 ≤ 50x ≤ 3500\r<BR>\n" );
document.write( "\n" );
document.write( "Divide all parts by 50:\r<BR>\n" );
document.write( "\n" );
document.write( "1800/50 ≤ x ≤ 3500/50<BR>\n" );
document.write( "36 ≤ x ≤ 70\r<BR>\n" );
document.write( "\n" );
document.write( "Therefore, the minimum area that could be used is 36 cm², and the maximum area is 70 cm².<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );