document.write( "Question 1209652: GetThere Airlines currently charges $200$ dollars per ticket and sells $40{,}000$ tickets a week. For every $10$ dollars they increase the ticket price, they sell $300$ fewer tickets a week. How many dollars should they charge to maximize their total revenue? \n" ); document.write( "
Algebra.Com's Answer #849740 by CPhill(1959)\"\" \"About 
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Here's how to determine the ticket price that maximizes revenue for GetThere Airlines:\r
\n" ); document.write( "\n" ); document.write( "1. **Define variables:**\r
\n" ); document.write( "\n" ); document.write( "* Let 'x' be the number of $10 price increases.
\n" ); document.write( "* Let 'P' be the ticket price.
\n" ); document.write( "* Let 'Q' be the number of tickets sold.
\n" ); document.write( "* Let 'R' be the total revenue.\r
\n" ); document.write( "\n" ); document.write( "2. **Express price and quantity in terms of x:**\r
\n" ); document.write( "\n" ); document.write( "* Price: P = 200 + 10x
\n" ); document.write( "* Quantity: Q = 40000 - 300x\r
\n" ); document.write( "\n" ); document.write( "3. **Write the revenue function:**\r
\n" ); document.write( "\n" ); document.write( "Revenue is price times quantity:\r
\n" ); document.write( "\n" ); document.write( "R(x) = P * Q
\n" ); document.write( "R(x) = (200 + 10x)(40000 - 300x)\r
\n" ); document.write( "\n" ); document.write( "4. **Expand the revenue function:**\r
\n" ); document.write( "\n" ); document.write( "R(x) = 8000000 - 60000x + 400000x - 3000x²
\n" ); document.write( "R(x) = -3000x² + 340000x + 8000000\r
\n" ); document.write( "\n" ); document.write( "5. **Find the vertex of the parabola:**\r
\n" ); document.write( "\n" ); document.write( "Since the revenue function is a quadratic with a negative leading coefficient, it represents a parabola opening downwards. The vertex will give the maximum revenue. The x-coordinate of the vertex is given by:\r
\n" ); document.write( "\n" ); document.write( "x = -b / 2a
\n" ); document.write( "x = -340000 / (2 * -3000)
\n" ); document.write( "x = -340000 / -6000
\n" ); document.write( "x = 56.67 (approximately)\r
\n" ); document.write( "\n" ); document.write( "6. **Determine the optimal price:**\r
\n" ); document.write( "\n" ); document.write( "Substitute the value of x back into the price equation:\r
\n" ); document.write( "\n" ); document.write( "P = 200 + 10x
\n" ); document.write( "P = 200 + 10 * 56.67
\n" ); document.write( "P = 200 + 566.7
\n" ); document.write( "P = $766.70\r
\n" ); document.write( "\n" ); document.write( "7. **Round to the nearest dollar:**\r
\n" ); document.write( "\n" ); document.write( "Since we're dealing with money, we should round the price to the nearest dollar. In this case, since x represents the number of $10 increases, we should use x = 56 or x = 57.\r
\n" ); document.write( "\n" ); document.write( "If x = 56, P = 200 + 10*56 = $760.
\n" ); document.write( "If x = 57, P = 200 + 10*57 = $770.\r
\n" ); document.write( "\n" ); document.write( "Let's calculate the revenue for both:
\n" ); document.write( "R(56) = (760)(40000 - 300*56) = 760 * 23200 = $17,632,000
\n" ); document.write( "R(57) = (770)(40000 - 300*57) = 770 * 22900 = $17,633,000\r
\n" ); document.write( "\n" ); document.write( "So, the maximum revenue occurs at $770.\r
\n" ); document.write( "\n" ); document.write( "**Answer:** They should charge $770 per ticket to maximize their total revenue.
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