document.write( "Question 1209633: Find all complex numbers z such that |z - 1| = |z + 3| + |z - 2i|.
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Algebra.Com's Answer #849731 by CPhill(1959)\"\" \"About 
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Here's how to approach this problem:\r
\n" ); document.write( "\n" ); document.write( "1. **Geometric Interpretation:**\r
\n" ); document.write( "\n" ); document.write( "The equation |z - 1| represents the distance between the complex number z and the complex number 1 (which can be thought of as the point (1,0) in the complex plane).\r
\n" ); document.write( "\n" ); document.write( "|z + 3| represents the distance between z and -3 (or (-3,0)).\r
\n" ); document.write( "\n" ); document.write( "|z - 2i| represents the distance between z and 2i (or (0,2)).\r
\n" ); document.write( "\n" ); document.write( "The equation states that the distance from z to 1 is equal to the sum of the distances from z to -3 and z to 2i.\r
\n" ); document.write( "\n" ); document.write( "2. **Consider the Triangle Inequality:**\r
\n" ); document.write( "\n" ); document.write( "The triangle inequality states that for any complex numbers a, b, and c:\r
\n" ); document.write( "\n" ); document.write( "|a + b| ≤ |a| + |b|\r
\n" ); document.write( "\n" ); document.write( "Let a = z + 3 and b = z - 2i, then |z + 3 + z - 2i| ≤ |z+3| + |z-2i|
\n" ); document.write( "|2z + 3 - 2i| ≤ |z+3| + |z-2i|\r
\n" ); document.write( "\n" ); document.write( "We are given |z - 1| = |z + 3| + |z - 2i|.
\n" ); document.write( "If z were on the line segment joining -3 and 2i, then |z+3| + |z-2i| would equal the distance between -3 and 2i. In this case, |z-1| = |-3-2i| = √13. But z would be a real number between -3 and 0, or an imaginary number between 0 and 2i. Neither of these satisfy the equation.\r
\n" ); document.write( "\n" ); document.write( "3. **Try z = x + yi:**\r
\n" ); document.write( "\n" ); document.write( "Substitute z = x + yi into the equation:\r
\n" ); document.write( "\n" ); document.write( "|x + yi - 1| = |x + yi + 3| + |x + yi - 2i|
\n" ); document.write( "|(x - 1) + yi| = |(x + 3) + yi| + |x + (y - 2)i|
\n" ); document.write( "√((x - 1)² + y²) = √((x + 3)² + y²) + √(x² + (y - 2)²)\r
\n" ); document.write( "\n" ); document.write( "4. **Square both sides (carefully!):**\r
\n" ); document.write( "\n" ); document.write( "(x - 1)² + y² = (x + 3)² + y² + x² + (y - 2)² + 2√((x + 3)² + y²)(x² + (y - 2)²)
\n" ); document.write( "x² - 2x + 1 + y² = x² + 6x + 9 + y² + x² + y² - 4y + 4 + 2√((x + 3)² + y²)(x² + (y - 2)²)
\n" ); document.write( "-2x + 1 = 6x + 13 + x² + y² - 4y + 2√((x + 3)² + y²)(x² + (y - 2)²)
\n" ); document.write( "-8x - 12 = x² + y² - 4y + 2√((x + 3)² + y²)(x² + (y - 2)²)\r
\n" ); document.write( "\n" ); document.write( "This equation is getting very complicated.\r
\n" ); document.write( "\n" ); document.write( "5. **Consider specific cases:**\r
\n" ); document.write( "\n" ); document.write( "Since the geometric interpretation is difficult, and the algebraic substitution is messy, there may not be a simple solution.\r
\n" ); document.write( "\n" ); document.write( "If we let y=0, we have |x-1| = |x+3| + |x|.
\n" ); document.write( "If x > 1, x-1 = x+3+x which is impossible.
\n" ); document.write( "If -3< x < 1, 1-x = x+3+x which is impossible.
\n" ); document.write( "If x < -3, 1-x = -x-3-x so 1 = -3-x, and x=-4.
\n" ); document.write( "So z=-4 is one solution.\r
\n" ); document.write( "\n" ); document.write( "Since the algebra is so difficult, and we found one solution, it is possible there are no others.\r
\n" ); document.write( "\n" ); document.write( "**Conclusion:**\r
\n" ); document.write( "\n" ); document.write( "z = -4 is one solution. The presence of the square roots makes it very difficult to solve for other solutions algebraically. It's possible this is the only solution.
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