document.write( "Question 1209612: Suppose the domain of f is (-1,1). Define the function g by
\n" ); document.write( "g(x) = 5 - f(x) + f(5/x).
\n" ); document.write( "What is the domain of g?
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Algebra.Com's Answer #849665 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "f(5/x) is what we should focus on.
\n" ); document.write( "The input 5/x needs to be on the interval -1 < 5/x < 1, so it fits with the domain interval (-1,1).\r
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\n" ); document.write( "\n" ); document.write( "You should find that -1 < 5/x < 1 leads to either x < -5 or x > 5.
\n" ); document.write( "But none of those values are in the interval -1 < x < 1.\r
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\n" ); document.write( "\n" ); document.write( "Therefore the domain of g(x) is the empty set.\r
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\n" ); document.write( "\n" ); document.write( "Some examples:\r
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\n" ); document.write( "\n" ); document.write( "Let's try x = 0.5
\n" ); document.write( "g(x) = 5 - f(x) + f(5/x)
\n" ); document.write( "g(0.5) = 5 - f(0.5) + f(5/0.5)
\n" ); document.write( "g(0.5) = 5 - f(0.5) + f(10)
\n" ); document.write( "g(0.5) = 5 - f(0.5) + undefined
\n" ); document.write( "g(0.5) = undefined
\n" ); document.write( "This shows that x = 0.5 is not in the domain of g(x).
\n" ); document.write( "f(10) is undefined since f(x) is only defined when -1 < x < 1.\r
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\n" ); document.write( "\n" ); document.write( "Let's try x = 10
\n" ); document.write( "g(x) = 5 - f(x) + f(5/x)
\n" ); document.write( "g(10) = 5 - f(10) + f(5/10)
\n" ); document.write( "g(10) = 5 - f(10) + f(0.5)
\n" ); document.write( "g(10) = 5 - undefined + f(0.5)
\n" ); document.write( "g(10) = undefined
\n" ); document.write( "We run into the same problem as before.
\n" ); document.write( "This shows that x = 10 is not in the domain of g(x).\r
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\n" ); document.write( "\n" ); document.write( "I encourage the student to explore other examples.
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