document.write( "Question 1209588: ((A & B) & C) & D, (D & C) → F, (B & C) → G, (A & D) → H ├ H & (G & F)\r
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Algebra.Com's Answer #849595 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " 1. ((A & B) & C) & D, \r\n" ); document.write( " 2. (D & C) → F, \r\n" ); document.write( " 3. (B & C) → G,\r\n" ); document.write( " 4. (A & D) → H ├ H & (G & F)\r\n" ); document.write( "\r\n" ); document.write( " 5. (A & B) & C 1, Simplification\r\n" ); document.write( " 6. A & B 5, Simplification\r\n" ); document.write( " 7. A 6, Simplification \r\n" ); document.write( " 8. B & A 6, Commutation\r\n" ); document.write( " 9. B 8, Simplification \r\n" ); document.write( "10. C & (A & B) 5, Commutation\r\n" ); document.write( "11. C 10, Simplification\r\n" ); document.write( "12. D & ((A & B) & C) 1, Commutation\r\n" ); document.write( "13. D 12, Simplification\r\n" ); document.write( "14. A & D 7,13, Conjunction\r\n" ); document.write( "15. H 4, Modus Ponens\r\n" ); document.write( "16. B & C 9,11, Conjunction\r\n" ); document.write( "17. G 3,16, Modus ponens\r\n" ); document.write( "18. D & C 13,11, Conjunction\r\n" ); document.write( "19. F 2,15, Modus Ponens\r\n" ); document.write( "20. G & F 17,19, Conjunction\r\n" ); document.write( "21. H & (G & F) 15,20, Conjunction\r\n" ); document.write( "\r\n" ); document.write( " \r\n" ); document.write( "Edwin\n" ); document.write( " |