document.write( "Question 1209582: If cot²αcot²β = 3,
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Algebra.Com's Answer #849570 by Edwin McCravy(20054)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "I think we can get by just using the standard trig identities that we're\r\n" );
document.write( "all accustomed to using, even though it might take a little longer:\r\n" );
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document.write( "\"cot%5E2%28alpha%29cot%5E2%28beta%29\"\"%22%22=%22%22\"\"3\"\r\n" );
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document.write( "\"%22%22=%22%22\"\"3\"\r\n" );
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document.write( "\"%22%22=%22%22\"\"3\"\r\n" );
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document.write( "\"%22%22=%22%22\"\"3\"\r\n" );
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document.write( "\"1-sin%5E2%28alpha%29-sin%5E2%28beta%29%2Bsin%5E2%28alpha%29sin%5E2%28beta%29\"\"%22%22=%22%22\"\"3%28sin%5E2%28alpha%29sin%5E2%28beta%29%5E%22%22%29\"\r\n" );
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document.write( "\"1-sin%5E2%28alpha%29-sin%5E2%28beta%29\"\"%22%22=%22%22\"\"2%28sin%5E2%28alpha%29sin%5E2%28beta%29%5E%22%22%29\"\r\n" );
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document.write( "\"1\"\"%22%22=%22%22\"\"sin%5E2%28alpha%29%2B+2sin%5E2%28alpha%29sin%5E2%28beta%29%2Bsin%5E2%28beta%29\" <-- call this equation 1\r\n" );
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document.write( "Now let's work on\r\n" );
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document.write( "\"%282-cos%282alpha%29%5E%22%22%29%282-cos%282beta%29%5E%22%22%29\"\r\n" );
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document.write( "\"%281%2B2sin%5E2%28alpha%29%5E%22%22%29%281%2B2sin%5E2%28beta%29%5E%22%22%29\"\r\n" );
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document.write( "\"1%2B2sin%5E2%28alpha%29%2B2sin%5E2%28beta%29%2B4sin%5E2%28alpha%29sin%5E2%28beta%29\"\r\n" );
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document.write( "Now look up at equation 1 and you see that what's in the big parentheses\r\n" );
document.write( "here is equal to 1, so,\r\n" );
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document.write( "\"1%2B2%281%29\"\"%22%22=%22%22\"\"3\"\r\n" );
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document.write( "So the answer is 3.\r\n" );
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document.write( "Edwin
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