document.write( "Question 1186068: Suppose events A and B are independent and\r
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Algebra.Com's Answer #849487 by ikleyn(52782)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Suppose events A and B are independent and\r\n" );
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document.write( "P(A) = 1/4\r\n" );
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document.write( "P(B) = 1/5\r\n" );
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document.write( "Find the probability. (Enter the probability as a fraction.)\r\n" );
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document.write( " P(A ∩ B)  the line is above a and b only\r\n" );
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\n" ); document.write( "\n" ); document.write( "        The solution in the post by @CPhill is incorrect, \r
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document.write( "The fact that  \" the line is above A and B only \"  means, that the question is about P(\"A%5Ec\"\"B%5Ec\"),\r\n" );
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document.write( "where  \"A%5Ec\" is the complement to A  and  \"B%5Ec\" is the complement to B.\r\n" );
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document.write( "We have then  \"P%28A%5Ec%29\" = 1 - 1/4 = 3/4  and  \"P%28B%5Ec%29\" = 1 - 1/5 = 4/5.\r\n" );
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document.write( "Since events A and B are independent,  the events  \"A%5Ec\"  and  \"B%5Ec\"  are independent, too.\r\n" );
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document.write( "Therefore,  P(\"A%5Ec\"\"B%5Ec\")}}} = \"P%28A%5Ec%29%2AP%28B%5Ec%29\" = \"%283%2F4%29%2A%284%2F5%29\" = \"3%2F5\".    ANSWER\r\n" );
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