document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1208817>Question 1208817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You plan to conduct a survey to find what proportion of the workforce has two or more jobs. You decide on the 99% confidence level and a margin of error of 2%. A pilot survey reveals that 8 of the 47 sampled hold two or more jobs. (Use t Distribution Table & z Distribution Table.)\r<BR>\n" );
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document.write( "How many in the workforce should be interviewed to meet your requirements? (Round z-score to 2 decimal places. Round up your answer to the next whole number.)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #849464 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=849464\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the point estimate is 0.170 and the sd=sqrt (0.170*0.830)/47)=0.053); that *2.58 z(0.995) =0.14 margin of error.<BR>\n" );
document.write( "99% CI for the estimate is (0.03, 0.31)<BR>\n" );
document.write( "margin of error=z*sqrt(0.17*0.83)/n<BR>\n" );
document.write( ".02=2.58*sqrt(.17*.83)/n)<BR>\n" );
document.write( "square both sides and rearrange<BR>\n" );
document.write( "0.0004n=6.66*0.14<BR>\n" );
document.write( "n=2331\r<BR>\n" );
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