document.write( "Question 1186596: In a recent poll, 580 people were asked if they liked dogs, and 22% said they did. Find the margin of error of this poll, at the 95% confidence level.\r
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document.write( "Give your answer to three decimals
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Algebra.Com's Answer #849425 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Here's how to calculate the margin of error for this poll:\r \n" ); document.write( "\n" ); document.write( "1. **Identify the key values:**\r \n" ); document.write( "\n" ); document.write( "* Sample size (n) = 580 \n" ); document.write( "* Sample proportion (p̂) = 0.22 (22% expressed as a decimal) \n" ); document.write( "* Confidence level = 95%\r \n" ); document.write( "\n" ); document.write( "2. **Find the critical z-score:**\r \n" ); document.write( "\n" ); document.write( "* For a 95% confidence level, the alpha (α) is 1 - 0.95 = 0.05. \n" ); document.write( "* Since we are dealing with a two-tailed confidence interval, we divide alpha by 2: 0.05 / 2 = 0.025 \n" ); document.write( "* The z-score corresponding to 0.025 in each tail (or 0.975 in the center) is 1.96. You can find this using a z-table or calculator.\r \n" ); document.write( "\n" ); document.write( "3. **Calculate the standard error:**\r \n" ); document.write( "\n" ); document.write( "* Standard Error (SE) = sqrt[ (p̂ * (1 - p̂)) / n ] \n" ); document.write( "* SE = sqrt[ (0.22 * (1 - 0.22)) / 580 ] \n" ); document.write( "* SE = sqrt[ (0.22 * 0.78) / 580 ] \n" ); document.write( "* SE = sqrt(0.1716 / 580) \n" ); document.write( "* SE ≈ sqrt(0.00029586) \n" ); document.write( "* SE ≈ 0.0172\r \n" ); document.write( "\n" ); document.write( "4. **Calculate the margin of error:**\r \n" ); document.write( "\n" ); document.write( "* Margin of Error (ME) = z * SE \n" ); document.write( "* ME = 1.96 * 0.0172 \n" ); document.write( "* ME ≈ 0.0337\r \n" ); document.write( "\n" ); document.write( "5. **Round to three decimals:**\r \n" ); document.write( "\n" ); document.write( "* ME ≈ 0.034\r \n" ); document.write( "\n" ); document.write( "Therefore, the margin of error of this poll, at the 95% confidence level, is approximately 0.034. \n" ); document.write( " \n" ); document.write( " |