document.write( "Question 1209538: The top of a cone of height 10cm and base radius 7cm is cut off by a plane parallel to the base. If the distance between the plane and the base is 3cm, calculate the volume of the remaining object. [Take π = 22/7] \n" ); document.write( "
Algebra.Com's Answer #849381 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "The top of a cone of height 10cm and base radius 7cm is cut off by a plane parallel to the base.
\n" ); document.write( "If the distance between the plane and the base is 3cm, calculate the volume of the remaining object. [Take π = 22/7]
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\n" ); document.write( "\n" ); document.write( "            Here is another,  more simple,  more straightforward \r
\n" ); document.write( "\n" ); document.write( "            and computationally less extensive solving method.\r
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document.write( "The volume of the original cone is  V = \"%281%2F3%29%2Api%2Ar%5E2%2Ah\" = \"%281%2F3%29%2A%2822%2F7%29%2A7%5E2%2A10\" = 513.33333 cm^3.\r\n" );
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document.write( "The smaller cone is similar to the original one with the similarity coefficient \"%2810-3%29%2F10\" = \"7%2F10\" = 0.7.\r\n" );
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document.write( "Therefore, the volume of the smaller cone is  \"0.7%5E3%2AV\" = \"0.7%5E3%2A513.33333\" = 176.07533 cm^3.\r\n" );
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document.write( "The volume of the interest is the difference  513.33333 - 176.07533 = 337.26 cm^3.\r\n" );
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document.write( "ANSWER<.  The volume of the remaining object is  337.26 cm^3  (approximately).\r\n" );
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\n" ); document.write( "\n" ); document.write( "Solved in different way.\r
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