document.write( "Question 1188789: (1 point) The weights of unicorns are normally distributed. Suppose that a simple random sample of 12 unicorns have a standard deviation of 20.8. Estimate the standard deviation of the entire population with 80% confidence.\r
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\n" ); document.write( "UCL =
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Algebra.Com's Answer #849294 by CPhill(1959)\"\" \"About 
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Here's how to calculate the confidence interval for the population standard deviation:\r
\n" ); document.write( "\n" ); document.write( "**1. Identify the given information:**\r
\n" ); document.write( "\n" ); document.write( "* Sample size (n) = 12
\n" ); document.write( "* Sample standard deviation (s) = 20.8
\n" ); document.write( "* Confidence level = 80%\r
\n" ); document.write( "\n" ); document.write( "**2. Find the degrees of freedom:**\r
\n" ); document.write( "\n" ); document.write( "Degrees of freedom (df) = n - 1 = 12 - 1 = 11\r
\n" ); document.write( "\n" ); document.write( "**3. Find the chi-square values:**\r
\n" ); document.write( "\n" ); document.write( "For an 80% confidence level, the alpha (α) is 1 - 0.80 = 0.20. We need to find the chi-square values for α/2 and 1-α/2.\r
\n" ); document.write( "\n" ); document.write( "* α/2 = 0.20 / 2 = 0.10
\n" ); document.write( "* 1 - α/2 = 1 - 0.10 = 0.90\r
\n" ); document.write( "\n" ); document.write( "Using a chi-square table or calculator, look up the values for df = 11:\r
\n" ); document.write( "\n" ); document.write( "* χ²(0.10, 11) ≈ 19.675
\n" ); document.write( "* χ²(0.90, 11) ≈ 5.578\r
\n" ); document.write( "\n" ); document.write( "**4. Calculate the lower confidence limit (LCL):**\r
\n" ); document.write( "\n" ); document.write( "LCL = sqrt[ (n-1) * s² / χ²(α/2, df) ]
\n" ); document.write( "LCL = sqrt[ (11 * 20.8²) / 19.675 ]
\n" ); document.write( "LCL = sqrt[ 4758.72 / 19.675 ]
\n" ); document.write( "LCL = sqrt[241.85]
\n" ); document.write( "LCL ≈ 15.55\r
\n" ); document.write( "\n" ); document.write( "**5. Calculate the upper confidence limit (UCL):**\r
\n" ); document.write( "\n" ); document.write( "UCL = sqrt[ (n-1) * s² / χ²(1-α/2, df) ]
\n" ); document.write( "UCL = sqrt[ (11 * 20.8²) / 5.578 ]
\n" ); document.write( "UCL = sqrt[ 4758.72 / 5.578 ]
\n" ); document.write( "UCL = sqrt[853.14]
\n" ); document.write( "UCL ≈ 29.21\r
\n" ); document.write( "\n" ); document.write( "**Answer:**\r
\n" ); document.write( "\n" ); document.write( "LCL ≈ 15.55
\n" ); document.write( "UCL ≈ 29.21\r
\n" ); document.write( "\n" ); document.write( "Therefore, we are 80% confident that the population standard deviation of unicorn weights is between approximately 15.55 and 29.21.
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