document.write( "Question 1188876: Use the finite universe method to prove that the following argument is invalid:
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document.write( "1. (x)Ax⊃(∃x)Bx
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document.write( "2. (∃x)Ax / (∃x)Bx \n" );
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Algebra.Com's Answer #849291 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Here's how to use the finite universe method to demonstrate the invalidity of the argument:\r \n" ); document.write( "\n" ); document.write( "1. Define a Finite Universe:\r \n" ); document.write( "\n" ); document.write( "Let the universe consist of just one object, which we'll call \"a.\" So, our universe U = {a}.\r \n" ); document.write( "\n" ); document.write( "2. Interpret the Premises and Conclusion:\r \n" ); document.write( "\n" ); document.write( "Premise 1: (x)Ax ⊃ (∃x)Bx becomes (Aa ⊃ Ba). This means \"If everything has property A, then there is something that has property B.\" \n" ); document.write( "Premise 2: (∃x)Ax becomes Aa. This means \"There is something that has property A\" (In our universe, this means 'a' has property A). \n" ); document.write( "Conclusion: (∃x)Bx becomes Ba. This means \"There is something that has property B\" (In our universe, this means 'a' has property B). \n" ); document.write( "3. Assign Truth Values:\r \n" ); document.write( "\n" ); document.write( "We need to assign truth values (True or False) to the properties A and B for the object 'a' in such a way that the premises are true, but the conclusion is false.\r \n" ); document.write( "\n" ); document.write( "Let Aa be True. ('a' has property A). \n" ); document.write( "Let Ba be False. ('a' does not have property B). \n" ); document.write( "4. Evaluate the Premises:\r \n" ); document.write( "\n" ); document.write( "Premise 1: (Aa ⊃ Ba) becomes (True ⊃ False), which is False. \n" ); document.write( "Since premise 1 is false, the argument is invalid.\r \n" ); document.write( "\n" ); document.write( "Explanation:\r \n" ); document.write( "\n" ); document.write( "We have created a scenario where 'a' has property A (Aa is True) and 'a' does not have property B (Ba is False). This makes Premise 2 (∃x)Ax true. However, the conclusion (∃x)Bx is false.\r \n" ); document.write( "\n" ); document.write( "The crucial point is Premise 1 (x)Ax ⊃ (∃x)Bx. This premise becomes false in our model. Since we could make the premises true while the conclusion is false, the argument is invalid. \n" ); document.write( " |