document.write( "Question 1191348: \"An electrical firm manufactures light bulbs that have a length of life that is approximately normally distributed, with mean equal to 802 hours and a standard deviation of 93 hours. Find the probability that a random samples of 23 bulbs will have an average life between 793 and 817 hours.\"
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Algebra.Com's Answer #849222 by CPhill(1959)\"\" \"About 
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Here's how to solve this problem:\r
\n" ); document.write( "\n" ); document.write( "1. **Find the standard error of the mean:**\r
\n" ); document.write( "\n" ); document.write( "The standard error of the mean (SEM) is the standard deviation of the sample means. It's calculated as:\r
\n" ); document.write( "\n" ); document.write( "SEM = σ / √n\r
\n" ); document.write( "\n" ); document.write( "Where:
\n" ); document.write( "* σ is the population standard deviation (93 hours)
\n" ); document.write( "* n is the sample size (23 bulbs)\r
\n" ); document.write( "\n" ); document.write( "SEM = 93 / √23 ≈ 19.38\r
\n" ); document.write( "\n" ); document.write( "2. **Calculate the z-scores:**\r
\n" ); document.write( "\n" ); document.write( "We need to convert the given average life values (793 and 817 hours) into z-scores. The z-score tells us how many standard errors a particular sample mean is away from the population mean.\r
\n" ); document.write( "\n" ); document.write( "z = (x - μ) / SEM\r
\n" ); document.write( "\n" ); document.write( "Where:
\n" ); document.write( "* x is the sample mean
\n" ); document.write( "* μ is the population mean (802 hours)\r
\n" ); document.write( "\n" ); document.write( "* For x = 793 hours:
\n" ); document.write( " z₁ = (793 - 802) / 19.38 ≈ -0.47\r
\n" ); document.write( "\n" ); document.write( "* For x = 817 hours:
\n" ); document.write( " z₂ = (817 - 802) / 19.38 ≈ 0.78\r
\n" ); document.write( "\n" ); document.write( "3. **Find the probabilities:**\r
\n" ); document.write( "\n" ); document.write( "Use a z-table or calculator to find the area under the normal curve between these two z-scores. This represents the probability that the sample mean will fall between 793 and 817 hours.\r
\n" ); document.write( "\n" ); document.write( "* Find the probability associated with z₂ = 0.78: P(z < 0.78) ≈ 0.7823
\n" ); document.write( "* Find the probability associated with z₁ = -0.47: P(z < -0.47) ≈ 0.3192\r
\n" ); document.write( "\n" ); document.write( "4. **Calculate the probability between the two values:**\r
\n" ); document.write( "\n" ); document.write( "Subtract the smaller probability from the larger probability:\r
\n" ); document.write( "\n" ); document.write( "P(-0.47 < z < 0.78) = P(z < 0.78) - P(z < -0.47)
\n" ); document.write( "P(-0.47 < z < 0.78) = 0.7823 - 0.3192 ≈ 0.4631\r
\n" ); document.write( "\n" ); document.write( "Therefore, the probability that a random sample of 23 bulbs will have an average life between 793 and 817 hours is approximately 0.4631 or 46.31%.
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