document.write( "Question 1190883: Write the equation of the ELLIPSE that satisfies the given conditions \r
\n" ); document.write( "\n" ); document.write( "d. Vertices (-5,0) and (5,0) length of latus rectum 8/5\r
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Algebra.Com's Answer #849182 by CPhill(1959)\"\" \"About 
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Here's how to find the equation of the ellipse:\r
\n" ); document.write( "\n" ); document.write( "**1. Center and Orientation:**\r
\n" ); document.write( "\n" ); document.write( "The vertices are at (-5,0) and (5,0). This tells us:\r
\n" ); document.write( "\n" ); document.write( "* The center of the ellipse is at the origin (0,0).
\n" ); document.write( "* The major axis is horizontal (along the x-axis).\r
\n" ); document.write( "\n" ); document.write( "**2. Value of 'a':**\r
\n" ); document.write( "\n" ); document.write( "The distance from the center to a vertex is 'a'. Since the vertices are at (-5,0) and (5,0), we have a = 5.\r
\n" ); document.write( "\n" ); document.write( "**3. Latus Rectum:**\r
\n" ); document.write( "\n" ); document.write( "The length of the latus rectum is given as 8/5. The formula for the latus rectum is (2b²)/a.\r
\n" ); document.write( "\n" ); document.write( "**4. Solve for 'b²':**\r
\n" ); document.write( "\n" ); document.write( "We can use the latus rectum length and the value of 'a' to solve for b²:\r
\n" ); document.write( "\n" ); document.write( "8/5 = (2b²) / 5
\n" ); document.write( "8 = 2b²
\n" ); document.write( "b² = 4\r
\n" ); document.write( "\n" ); document.write( "**5. Equation of the Ellipse:**\r
\n" ); document.write( "\n" ); document.write( "Since the major axis is horizontal, the standard form of the equation is:\r
\n" ); document.write( "\n" ); document.write( "(x²/a²) + (y²/b²) = 1\r
\n" ); document.write( "\n" ); document.write( "Substitute the values of a² and b²:\r
\n" ); document.write( "\n" ); document.write( "(x²/5²) + (y²/4) = 1
\n" ); document.write( "(x²/25) + (y²/4) = 1\r
\n" ); document.write( "\n" ); document.write( "Therefore, the equation of the ellipse is (x²/25) + (y²/4) = 1.
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