document.write( "Question 1190992: Ten people (5 men and 5 women) are attending a dinner party. In how many ways can they be arranged if:\r
\n" ); document.write( "\n" ); document.write( "a. they are to be arranged in a line for a picture?\r
\n" ); document.write( "\n" ); document.write( "b. They are to be arranged with men and women alternating around the table?\r
\n" ); document.write( "\n" ); document.write( "c. they are arranged in a line for a picture but the man and women must alternate?
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Algebra.Com's Answer #849175 by CPhill(1959)\"\" \"About 
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**a. Arrangements in a line:**\r
\n" ); document.write( "\n" ); document.write( "There are 10 people in total, so there are 10! (10 factorial) ways to arrange them in a line.\r
\n" ); document.write( "\n" ); document.write( "10! = 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 = 3,628,800\r
\n" ); document.write( "\n" ); document.write( "**b. Arrangements with men and women alternating around a table:**\r
\n" ); document.write( "\n" ); document.write( "Since there are 5 men and 5 women, they can alternate in two ways: M W M W M W M W M W or W M W M W M W M W M. \r
\n" ); document.write( "\n" ); document.write( "First, arrange the men. There are 5 men, so there are 5! ways to arrange them. Similarly, there are 5! ways to arrange the women.\r
\n" ); document.write( "\n" ); document.write( "So, the total number of arrangements is 2 × 5! × 5! = 2 × 120 × 120 = 28,800.\r
\n" ); document.write( "\n" ); document.write( "**c. Arrangements in a line with men and women alternating:**\r
\n" ); document.write( "\n" ); document.write( "Similar to the table arrangement, there are two possible alternating patterns: M W M W M W M W M W or W M W M W M W M W M.\r
\n" ); document.write( "\n" ); document.write( "The number of ways to arrange the men is 5! and the number of ways to arrange the women is 5!.\r
\n" ); document.write( "\n" ); document.write( "So, the total number of arrangements is 2 × 5! × 5! = 2 × 120 × 120 = 28,800.\r
\n" ); document.write( "\n" ); document.write( "**Final Answers:**\r
\n" ); document.write( "\n" ); document.write( "a. 3,628,800 ways
\n" ); document.write( "b. 28,800 ways
\n" ); document.write( "c. 28,800 ways
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