document.write( "Question 1191373: Find each Poisson probability, using a mean arrival rate of 10 arrivals per hour.\r
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document.write( "(c) Fewer than five arrivals. (Round your answer to 4 decimal places.)
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document.write( " Poisson probability: \r
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document.write( "(d) At least 11 arrivals. (Round your answer to 4 decimal places.)
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document.write( " Poisson probability: \n" );
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Algebra.Com's Answer #849173 by CPhill(1959)![]() ![]() You can put this solution on YOUR website! Here's how to calculate the Poisson probabilities:\r \n" ); document.write( "\n" ); document.write( "**Understanding the Poisson Distribution**\r \n" ); document.write( "\n" ); document.write( "The Poisson distribution is used to model the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known average rate and independently of the time since the last event. The formula is:\r \n" ); document.write( "\n" ); document.write( "P(x) = (e^(-λ) * λ^x) / x!\r \n" ); document.write( "\n" ); document.write( "Where:\r \n" ); document.write( "\n" ); document.write( "* P(x) is the probability of x events occurring \n" ); document.write( "* e is the base of the natural logarithm (approximately 2.71828) \n" ); document.write( "* λ is the average number of events (arrivals) per interval (10 in this case) \n" ); document.write( "* x is the number of events we're interested in \n" ); document.write( "* x! is the factorial of x\r \n" ); document.write( "\n" ); document.write( "**c) Fewer than five arrivals (x < 5):**\r \n" ); document.write( "\n" ); document.write( "We need to calculate P(0) + P(1) + P(2) + P(3) + P(4).\r \n" ); document.write( "\n" ); document.write( "* P(0) = (e^-10 * 10^0) / 0! ≈ 0.000045 \n" ); document.write( "* P(1) = (e^-10 * 10^1) / 1! ≈ 0.000454 \n" ); document.write( "* P(2) = (e^-10 * 10^2) / 2! ≈ 0.002270 \n" ); document.write( "* P(3) = (e^-10 * 10^3) / 3! ≈ 0.007567 \n" ); document.write( "* P(4) = (e^-10 * 10^4) / 4! ≈ 0.018918\r \n" ); document.write( "\n" ); document.write( "P(x < 5) = P(0) + P(1) + P(2) + P(3) + P(4) ≈ 0.000045 + 0.000454 + 0.002270 + 0.007567 + 0.018918 ≈ 0.029254\r \n" ); document.write( "\n" ); document.write( "Rounded to 4 decimal places, the probability is 0.0293.\r \n" ); document.write( "\n" ); document.write( "**d) At least 11 arrivals (x ≥ 11):**\r \n" ); document.write( "\n" ); document.write( "It's easier to calculate the complement and subtract from 1. That is:\r \n" ); document.write( "\n" ); document.write( "P(x ≥ 11) = 1 - P(x < 11) = 1 - [P(0) + P(1) + ... + P(10)]\r \n" ); document.write( "\n" ); document.write( "Calculating each individual probability from P(0) to P(10) and summing them can be tedious. It's best to use a calculator or statistical software that has built-in Poisson cumulative distribution functions (CDF). \n" ); document.write( "Using a calculator or software, you'll find that P(x < 11) ≈ 0.5830.\r \n" ); document.write( "\n" ); document.write( "Therefore, P(x ≥ 11) = 1 - 0.5830 = 0.4170\r \n" ); document.write( "\n" ); document.write( "Rounded to 4 decimal places, the probability is 0.4170. \n" ); document.write( " \n" ); document.write( " |