document.write( "Question 1191696: 2. Then grade point averages of 20 college students selected at random from the graduating class are as follows:\r
\n" ); document.write( "\n" ); document.write( "3.2 1.9 2.7 2.4
\n" ); document.write( "2.8 2.9 3.8 3.0
\n" ); document.write( " 2.5 3.3 1.8 2.5
\n" ); document.write( " 3.7 2.8 2.0 3.2
\n" ); document.write( " 2.3 2.1 2.5 1.9\r
\n" ); document.write( "\n" ); document.write( "a. Calculate the descriptive statistics.
\n" ); document.write( "b. Use the appropriate graph for the GPA of the 20 students.
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Algebra.Com's Answer #849145 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
Here's the solution:\r
\n" ); document.write( "\n" ); document.write( "**a. Descriptive Statistics**\r
\n" ); document.write( "\n" ); document.write( "First, let's organize the data in ascending order to make calculations easier:\r
\n" ); document.write( "\n" ); document.write( "1.8, 1.9, 1.9, 2.0, 2.1, 2.3, 2.4, 2.5, 2.5, 2.5, 2.7, 2.8, 2.8, 2.9, 3.0, 3.2, 3.2, 3.3, 3.7, 3.8\r
\n" ); document.write( "\n" ); document.write( "Now we can calculate the descriptive statistics:\r
\n" ); document.write( "\n" ); document.write( "* **Mean:** (Sum of all values) / (Number of values)
\n" ); document.write( " Mean = (1.8 + 1.9 + 1.9 + 2.0 + 2.1 + 2.3 + 2.4 + 2.5 + 2.5 + 2.5 + 2.7 + 2.8 + 2.8 + 2.9 + 3.0 + 3.2 + 3.2 + 3.3 + 3.7 + 3.8) / 20
\n" ); document.write( " Mean = 51.5 / 20 = 2.575\r
\n" ); document.write( "\n" ); document.write( "* **Median:** The middle value (since there are 20 values, the median is the average of the 10th and 11th values)
\n" ); document.write( " Median = (2.5 + 2.7) / 2 = 2.6\r
\n" ); document.write( "\n" ); document.write( "* **Mode:** The most frequent value(s)
\n" ); document.write( " Mode = 2.5 (appears 3 times)\r
\n" ); document.write( "\n" ); document.write( "* **Range:** Maximum value - Minimum value
\n" ); document.write( " Range = 3.8 - 1.8 = 2.0\r
\n" ); document.write( "\n" ); document.write( "* **Variance:** The average of the squared differences from the mean. Here's how to calculate it:
\n" ); document.write( " 1. Subtract the mean from each value and square the result.
\n" ); document.write( " 2. Sum all the squared differences.
\n" ); document.write( " 3. Divide the sum by the number of values minus 1 (n-1 = 20-1 =19 for sample variance). This is called the sample variance.
\n" ); document.write( " Variance ≈ 0.355 (You can use a calculator or spreadsheet software for this).\r
\n" ); document.write( "\n" ); document.write( "* **Standard Deviation:** The square root of the variance
\n" ); document.write( " Standard Deviation ≈ √0.355 ≈ 0.596\r
\n" ); document.write( "\n" ); document.write( "**b. Appropriate Graph**\r
\n" ); document.write( "\n" ); document.write( "A **histogram** or a **stem-and-leaf plot** would be appropriate for visualizing the GPA data. A histogram is generally preferred for larger datasets. Here's what a histogram would look like conceptually:\r
\n" ); document.write( "\n" ); document.write( "* **X-axis:** GPA ranges (e.g., 1.8-2.0, 2.0-2.2, 2.2-2.4, ..., 3.8-4.0)
\n" ); document.write( "* **Y-axis:** Frequency (number of students in each GPA range)\r
\n" ); document.write( "\n" ); document.write( "You would then create bars for each GPA range, with the height of the bar representing the number of students whose GPAs fall within that range.\r
\n" ); document.write( "\n" ); document.write( "A stem-and-leaf plot would also be suitable, especially since the dataset is relatively small. It would show the individual data points while still giving a sense of the distribution. Here's how it would look:\r
\n" ); document.write( "\n" ); document.write( "```
\n" ); document.write( "1 | 899
\n" ); document.write( "2 | 01345557889
\n" ); document.write( "3 | 022378
\n" ); document.write( "```\r
\n" ); document.write( "\n" ); document.write( "Where the \"stem\" is the digit before the decimal point, and the \"leaves\" are the digits after the decimal point.\r
\n" ); document.write( "\n" ); document.write( "Both the histogram and stem-and-leaf plot would give you a visual representation of the distribution of GPAs among the 20 students.
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