document.write( "Question 1191300: Use the drawing in which
\n" ); document.write( "AC intersects DB
\n" ); document.write( " at point O to answer the question.\r
\n" ); document.write( "\n" ); document.write( "Two lines intersect at point O to form four angles.
\n" ); document.write( "Line A C goes from point A in the top left, through point O in the center, to point C in the bottom right.
\n" ); document.write( "Line D B goes from point D in the bottom left, through O on line A C, to point B in the top right.
\n" ); document.write( "The angle at the bottom, ∠C O D, is labeled 1.
\n" ); document.write( "The angle on the left, ∠D O A, is labeled 2.
\n" ); document.write( "The angle at the top, ∠A O B, is labeled 3.
\n" ); document.write( "The angle on the right, ∠B O C, is labeled 4.
\n" ); document.write( "If
\n" ); document.write( "m∠2 = \r
\n" ); document.write( "\n" ); document.write( "x
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\n" ); document.write( "m∠3 = \r
\n" ); document.write( "\n" ); document.write( "x
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\n" ); document.write( " + 60
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\n" ); document.write( " find x and m∠2 in degrees.
\n" ); document.write( "x =
\n" ); document.write( "m∠2 =
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Algebra.Com's Answer #849120 by CPhill(1959)\"\" \"About 
You can put this solution on YOUR website!
Here's how to solve for x and m∠2:\r
\n" ); document.write( "\n" ); document.write( "1. **Recognize the relationship between the angles:** ∠2 and ∠3 are vertical angles. Vertical angles are congruent, meaning they have the same measure.\r
\n" ); document.write( "\n" ); document.write( "2. **Set up an equation:** Since m∠2 = m∠3, we can write:\r
\n" ); document.write( "\n" ); document.write( " x² - 30 = x³ + 60\r
\n" ); document.write( "\n" ); document.write( "3. **Rearrange the equation:** To solve for x, we need to rearrange the equation. However, this equation involves x² and x³, which makes it a cubic equation, and isn't easy to solve directly. The problem likely intended a linear relationship. It is possible there was a typo in the original problem. If we assume that the intended relationship was linear rather than polynomial, and assuming that the intended measures were m∠2 = x - 30 and m∠3 = x + 60, then we can proceed as follows:\r
\n" ); document.write( "\n" ); document.write( " x - 30 = x + 60\r
\n" ); document.write( "\n" ); document.write( "4. **Solve for x:**
\n" ); document.write( " Subtract x from both sides:
\n" ); document.write( " -30 = 60 This is not possible.\r
\n" ); document.write( "\n" ); document.write( " It's possible that there was a typo in the original problem. If the angle measures were instead m∠2 = x - 30 and m∠3 = 2x + 60, then we would proceed as follows:\r
\n" ); document.write( "\n" ); document.write( " x - 30 = 2x + 60
\n" ); document.write( " -90 = x\r
\n" ); document.write( "\n" ); document.write( "5. **Substitute x back into the equation for m∠2:**\r
\n" ); document.write( "\n" ); document.write( " m∠2 = x - 30
\n" ); document.write( " m∠2 = -90 - 30
\n" ); document.write( " m∠2 = -120°\r
\n" ); document.write( "\n" ); document.write( "Since angle measures can't be negative, it's likely there was a typo in the original problem. Double-check the given angle measures. If they were m∠2 = x-30 and m∠3 = x+60, then there is no solution. If they were m∠2 = x-30 and m∠3 = 2x+60, then x = -90 and m∠2 = -120. \r
\n" ); document.write( "\n" ); document.write( "**If you can provide the correct angle measures, I can help you solve the problem accurately.**
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