document.write( "Question 17587: square x-2=3 solve by using graphing utility to verify the solution \n" ); document.write( "

Algebra.Com's Answer #8491 by rapaljer(4671) $\"\"$ $\"About$

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Assuming that you mean $\"sqrt%28x-2%29+=3\"$ , the first step is to set the equation equal to zero to write $\"sqrt%28x-2%29-3=0\"$ , and graph $\"y+=+sqrt%28x-2%29+-+3+\"$ . The solution will be the value(s) of x where this graph crosses the x axis. You can assume because of the square root that $\"x+%3E=+2\"$ . The value of x where the graph crosses the x axis is the solution for this equation:\r
\n" ); document.write( "\n" ); document.write( " $\"graph+%28600%2C300%2C+2%2C20%2C-10%2C10%2C+sqrt%28x-2%29-3%29+\"$ \r
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\n" ); document.write( "\n" ); document.write( "The normal graph for x from -10 to 10 may NOT work here. You may need to use a value of x larger than 10. Let's try graphing up to x= 20 and see if the graph crosses the x axis. It turns out that x= 11 is the value that works, so this is the solution. X=11, and it checks also!\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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